Y=12
Add 3 to both sides add nine and 3 to get 12
W=6
Divide both sides by four divide 24 by 4 to get six
X=2
Subtract eight from both sides
subtract eight from 10 to get 2
Answer:
![\displaystyle c = \frac{20}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20c%20%3D%20%5Cfrac%7B20%7D%7B3%7D)
Step-by-step explanation:
According to Rolle's Theorem, if f(a) = f(b) in an interval [a, b], then there must exist at least one <em>c</em> within (a, b) such that f'(c) = 0.
We are given that g(5) = g(8) = -9. Then according to Rolle's Theorem, there must be a <em>c</em> in (5, 8) such that g'(c) = 0.
So, differentiate the function. We can take the derivative of both sides with respect to <em>x: </em>
<em />
<em />
Differentiate:
![g'(x) = -21x^2+182x-280](https://tex.z-dn.net/?f=g%27%28x%29%20%3D%20-21x%5E2%2B182x-280)
Let g'(x) = 0:
![0 = -21x^2+182x-280](https://tex.z-dn.net/?f=0%20%3D%20-21x%5E2%2B182x-280)
Solve for <em>x</em>. First, divide everything by negative seven:
![0=3x^2-26x+40](https://tex.z-dn.net/?f=0%3D3x%5E2-26x%2B40)
Factor:
<h3>
![0=(x-2)(3x-20)](https://tex.z-dn.net/?f=0%3D%28x-2%29%283x-20%29)
</h3>
Zero Product Property:
![x-2=0 \text{ or } 3x-20=0](https://tex.z-dn.net/?f=x-2%3D0%20%5Ctext%7B%20or%20%7D%203x-20%3D0)
Solve for each case. Hence:
![\displaystyle x=2 \text{ or } x = \frac{20}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D2%20%5Ctext%7B%20or%20%7D%20x%20%3D%20%5Cfrac%7B20%7D%7B3%7D)
Since the first solution is not within our interval, we can ignore it.
Therefore:
![\displaystyle c = \frac{20}{3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20c%20%3D%20%5Cfrac%7B20%7D%7B3%7D)
2.6/1.3 * (10^9/10^2)
2*10^7
Y = kx
72 = k*3
73/3 = k
24 = k
y = 24x
Answer:
a+4b-24
Step-by-step explanation:
4(1/4a+b−6)
=(4)(1/4a+b+−6)
=(4)(1/4a)+(4)(b)+(4)(−6)
=a+4b−24