Question

What are the measurements of the sides of a pentagon that has the area of 32?

Answer 1

Answer:

4.31 units

Step-by-step explanation:

A pentagon is a polygon with five straight sides.

The formula to apply here will be finding area from side length, assuming that this is  a regular pentagon with five sides of equal length.

Lets take each side length to be x units

Divide the pentagon into five triangles by joining a line from the center to any vertex of the pentagon.

Now you have five equal triangle.Take the base triangle and divide it into two(take a line from center of pentagon to hit the base at 90°)

This will divide the base triangle of length x unit into two equal triangles with base length x/2 units.

The angle at the pentagon center for the small formed triangle will be 36°. Here you have a triangle with base x/2 units and angle 36° at top center.

To get the height of the triangle you apply formula for tangent of an angle;

height, h=0.5x /tan 36°

Find area of the small triangle;

Area=1/2 *b*h

where b is base length=0.5x and h is height = 0.5x/tan 36°

Area=1/2*0.5x * (0.5x /tan 36°) Area for one small triangle.

However, you notice that you will have 10 small triangles for the whole pentagon, hence multiply this area by 10 which should be equal to the area of the pentagon given 32.

32=1/2 * 0.5x *(0.5x /tan 36°) *10

32=1.25x² /tan 36°

32*0.7265=1.25x²

18.60=x²

√18.60=x

4.31=x

Measurement of one side is 4.31 units