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Vlada [557]
4 years ago
13

In the figure BC || DE . Angles__________

Mathematics
2 answers:
SashulF [63]4 years ago
6 0

Answer:

angles CAF and EFH, because they are corresponding angles and transitive  

Step-by-step explanation:

LiRa [457]4 years ago
4 0

Answer:

caf  and efa

Step-by-step explanation: corresponding angles and transitive

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Can you please help me
Sergio039 [100]

Take into account the length of the right side of the figure is 10. Moreover, x is the hypotenuse of a right triangle. To find the value of x, use the sine function:

cos 45 = opposite side/hypotenuse

cos 45 = 10/x solve for x

x = 10/cos 45

x = 10/0.707

x = 14.14

with the previous value of x, you can find y. Again, consider the right triangle right side. x is the hypotenuse. Use the Pythagorean theorem to find y:

x² = 10² + y² solve for y and replace x

y² = x² - 10²

y² = (14.14)² - 100

y² = 200 - 100

y² = 100 apply square root both sides

y = 10

Hence, the values of x and y are 14.14 and 10 respectively

7 0
1 year ago
Each of the letters in the word APPLE is on separate cards, face down on the table. If you pick a card at random, what is the pr
Lina20 [59]
Probability =

         (number of possible ways to succeed)
divided by
         (total number of possible outcomes) .

Number of ways to succeed = 2  (pick the 'A' or the 'L')

Total number of possible outcomes = 5 (the cards on the table) .

Probability of success  =  2/5  =  40% .
5 0
4 years ago
(12a^(2) - 3)/(2)*(2a + 1)^(-2)*((6)/((2a + 1)))^(-1)
Elena L [17]

Answer:

\frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

Step-by-step explanation:

\frac{(12a^2-3)}{2*(2a+1)^{-2}}*\frac{6}{(2a+1)^{-1} }\\ = \frac{(12a^2-3)}{2 * \frac{1}{(2a+1)^{2} }} * \frac{6}{\frac{1}{2a+1}  }\\ =\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}\\=\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}

= \frac{(12a^2-3)(4a^{2} + 1 + 2 (2a)(1))}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{1} * \frac{3}{2a+1}\\= \frac{3(12a^2-3)(4a^{2} + 1 + 4a)} {2a+1}\\\\= \frac{3(12a^2(4a^{2} + 1 + 4a) - 3 (4a^{2}+1+4a)} {2a+1}\\= \frac{3(48a^{4}+12a^{2}+48a^{3}  - 12a^{2} -12 - 4a)} {2a+1}\\= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a)} {2a+1}

= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a} {2a+1}\\= \frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

6 0
4 years ago
Do Now: Lesson Part 1
Morgarella [4.7K]

Answer:

A is the answer

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP, WILL GIVE BRAINLIEST!!!<br><br><br> Find the inverse of f(x)=6x-4<br> and find f^-1(62)
Lena [83]
Answer: 11

=========================

Explanation:

To find the inverse, or f^-1 of a function, you first replace the y= 6x-4 with x=6y-4

Finding the inverse from here is basically just finding y in terms of x.

1) x=6y-4
2) x+4=6
3) (x+4)/6= y

y= (x+4)/6 is now your f^-1.

Now that you have your inverse, replace 62 with your x in y=(x+4)/6

1) (62+4)/6
2) 66/6
3) 11

Therefore, f^-1(62)= 11

Hope this helps :)
5 0
3 years ago
Read 2 more answers
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