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never [62]
3 years ago
12

The temperature at a ski resort dropped from 6 Celsius to -5 Celsius.

Mathematics
1 answer:
Bezzdna [24]3 years ago
7 0
<span>The temperature at a ski resort dropped from 6 Celsius to -5 Celsius.  Suppose we are to calculate the magnitude of the drop.  That would be |6-(-5)| = 11 degrees C.  The actual change in temp was -11 deg. C.</span>
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Rashad had 25 stamps. He shared them equally among himself and 4 friends. Then rashad found 2 more stamps in his pocket. Write a
Dafna1 [17]
It would be written like so:

25/4 + 2

Though I'm not sure how you share 25 stamps among 4 friends equally without having to rip 1 of the 25 stamps into quarters.
5 0
3 years ago
Read 2 more answers
Please help me solve this
Lelechka [254]

Answer:

The measure of angle x is 115 degrees

Step-by-step explanation:

Supplementary angles are angles which, when added together, equal 180 degrees. So, subtracting 65 from 180 would get you the answer(115).

7 0
4 years ago
Which of the following statements must be true about this diagrarn? Check allthat applyA. The degree measure of 24 equals the su
vovangra [49]

In the given triangle we have the following:

A. The sum of the inner angles of a triangle is always equal to 180, that is:

\angle1+\angle2+\angle3=180

From this, we can solve for the sum of angles 1 and 2 and we get:

\angle1+\angle2=180-\angle3

Now, we also know that angles 3 and 4 are supplementary angles and therefore their sum is 180 degrees, that is:

\angle4+\angle3=180

Solving for angle 4:

\angle4=180-\angle3

Equating both results we get:

\angle1+\angle2=\angle4

Therefore, it is true that angle 4 is the sum of angles 1 and 2.

B. We have that the sum of angles 2 and 3 is:

\angle2+\angle3=180-\angle1

If this were equal to angle 4 we would have:

\begin{gathered} \angle4=180-\angle1 \\ \angle4+\angle1=180 \end{gathered}

B

8 0
1 year ago
Convert radian measurement of 3pi/7 into degrees
kompoz [17]

Answer:

I believe it’s 77.14

Step-by-step explanation:

8 0
4 years ago
please do the steps Solve for d: 1/6d-8=5/8 2. Solve for x: 3x-4+5x=10-2z 3. Solve for c: 7(c-3)=14 4. Solve for m: 11(m/22+3/44
xeze [42]

Answer:

d = 55.5  

x = 1

c = 11

m = \frac{1}{122}

k = \frac{a}{(c + 5)}

Step-by-step explanation:

Sorry, the formatting is slightly hard to understand, but I think this is what you meant.

Q1.

\frac{1}{6}d - 8 = \frac{5}{8} x 2

Step 1. Simplify.

\frac{5}{8} x 2 = \frac{5}{8} x \frac{2}{1} = \frac{10}{8}

Step 2. Cancel out the negative 8.

\frac{1}{6}d - 8 = \frac{10}{8}

+ 8 to both sides (do the opposite: \frac{1}{6}d is subtracting 8 right now, but to cancel that out, we will do the opposite of subtraction, i.e. addition)

\frac{1}{6}d = \frac{10}{8} + 8

Step 3. Simplify.

\frac{10}{8} + 8 = \frac{10}{8} + \frac{8}{1} = \frac{10}{8} + \frac{64}{8} = \frac{74}{8} = \frac{37}{4}

Step 4. Cancel out the \frac{1}{6}.

\frac{1}{6}d = \frac{37}{4}

÷ \frac{1}{6} from both sides (do the opposite: d is multiplied by \frac{1}{6} right now, but to cancel that out, we will do the opposite of multiplication, i.e. division)

÷ \frac{1}{6} = x 6

So....

x 6 to both sides

d = \frac{37}{4} x  6 = \frac{37}{4} x \frac{6}{1} = \frac{222}{4} = \frac{111}{2} = 55.5

Step 5. Write down your answer.

d = 55.5

Q2.

3x - 4 + 5x = 10 - 2x × 3

Step 1. Simplify

3x - 4 + 5x = 3x + 5x - 4 = 8x - 4

10 - 2x × 3 = 10 - (2x × 3) = 10 - 6x

Step 2. Cancel out the negative 6x

8x - 4 = 10 - 6x

+ 6x to both sides (do the opposite - you're probably tired of reading this now - right now it's 10 subtract 6x, but the opposite of subtraction is addition)

14x - 4 = 10

Step 3. Cancel out the negative 4

14x - 4 = 10

+ 4 to both sides (right now it's 14x subtract 4, but the opposite of subtraction is addition)

14x = 14

Step 4. Divide by 14

14x = 14

÷ 14 from both sides (out of the [14 × x] we only want the [x], so we cancel out the [× 14])

x = 1

Step 5. Write down your answer.

x = 1

Q3.

7(c - 3) = 14 × 4

Step 1. Expand the brackets

7(c - 3) = (7 x c) - (7 x 3) = 7c - 21

Step 2. Simplify

14 x 4 = 56

Step 3. Cancel out the negative 21

7c - 21 = 56

+ 21

7c = 56 + 21

7c = 77

Step 4. Cancel out the ×7

7c = 77

÷ 7

c = 77 ÷ 7

c = 11

Step 5. Write down your answer.

c = 11

Q4.

11(\frac{m}{22} + \frac{3}{44}) = 87m + m × 5

Step 1. Expand the brackets

11(\frac{m}{22} + \frac{3}{44}) = (11 x \frac{m}{22}) + (11 x \frac{3}{44}) = (\frac{11}{1} x \frac{m}{22}) + (\frac{11}{1} x \frac{3}{44}) = \frac{11m}{22} + \frac{33}{44} = \frac{m}{2} + \frac{3}{4}

Step 2. Simplify.

87m + m x 5 = 87m + 5m = 92m

Step 3. Cancel out the add \frac{3}{4}

\frac{m}{2} + \frac{3}{4} = 92m

- \frac{3}{4}

\frac{m}{2} = 92m - \frac{3}{4}

\frac{m}{2} = \frac{92m}{1} - \frac{3}{4}

\frac{m}{2} = \frac{368m}{4} - \frac{3}{4}

\frac{m}{2} = \frac{368m - 3}{4}

Step 4. Cancel out the ÷ 4

\frac{m}{2} = \frac{368m - 3}{4}

x 4

2m = 368m - 3

Step 5. Cancel out the 368m

2m = 368m - 3

- 368m

-366m = - 3

Step 6. Cancel out the × -366

-366m = -3

÷ -366

m = \frac{-3}{-366}

m = \frac{1}{122}

Step 7. Write down your answer.

m = \frac{1}{122}

Q5.

ck + 5k = a

Step 1. Factorise

ck + 5k = (c × k) + (5 × k) = (c + 5) x k = k(c + 5)

Step 2. Cancel out the × (c + 5)

k(c + 5) = a

÷ (c + 5)

k = a ÷ (c + 5)

k = \frac{a}{(c + 5)}

5 0
4 years ago
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