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Lyrx [107]
3 years ago
14

Given: NQ is an altitude of △MNP

Mathematics
1 answer:
Virty [35]3 years ago
8 0

Answer:

Statement:                                                       Reason:

ΔNQM and ΔNQP are right triangle           Definition of a right triangle

SinM = h/p  and SinP = h/m                        Definition of sine ratio

p sin M = m sin P                                          Substitution property of equality

p sin M / pm = msinP / pm                           Division property of equality.

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In a unit circle, ø = 2pi radians What is the terminal point?
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Answer:

The terminal point is (1, 0) ⇒ D

Step-by-step explanation:

In the unit circle, Ф is the angle between the terminal side and the positive part of the x-xis.

  • The terminal point on the positive part of the x-axis is (1, 0),which means Ф = 0° or 360° and cosФ = 1, sinФ = 0
  • The terminal point on the positive part of the y-axis is (0, 1),which means Ф = 90° and cosФ = 0, sinФ = 1
  • The terminal point on the negative part of the x-axis is (-1, 0),which means Ф = 180° and cosФ = -1, sinФ = 0
  • The terminal point on the negative part of the y-axis is (0, -1),which means Ф = 270° and cosФ = 0, sinФ = -1

In a unit circle

∵ Ф = 2π radians

∵ 2π radians = 360°

→ By using the 1st rule above

∴ The terminal point is (1, 0)

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