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vfiekz [6]
3 years ago
10

Please help me find x and y. Give a real answer that is correct.

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
7 0

Answers:

x = 5/2 = 2.5

y = 10

============================================

Explanation:

Focus on the smallest triangle and the medium sized triangle. We can form the proportion 2/4 = x/5 by dividing the corresponding sides together.

Solving for x leads us to the following

2/4 = x/5

2*5 = 4*x

10 = 4x

4x = 10

x = 10/4

x = 5/2

x = 2.5

-----------------

Now focus on the medium sized triangle and the largest triangle. We'll use the same idea as before

4/8 = 5/y

4y = 8*5

4y = 40

y = 40/4

y = 10

Note how each horizontal line is a midsegment, which means that jumping from y = 10 to 5 is us taking half of that value. Then going from 5 to x = 5/2 = 2.5 is another step of cutting in half.

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borishaifa [10]

Answer:

$5.20

Step-by-step explanation:

Find the tax rate first:

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-------------- = 0.04

 $30.00

The tax rate is 4%.

Then the tax on a $130 item is 0.04($130) = $5.20

7 0
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How much time has<br> Passed from 6:25.Am<br> Unitil 10:25 pm
stealth61 [152]
16 hours has passed
6 0
3 years ago
A restaurant offers a combo special with 3 different sandwiches, 2 different salads, and 5 different drinks. From how many diffe
m_a_m_a [10]

Answer:

30 ways

Step-by-step explanation:

Given the following information:

  • 3 different sandwiches
  • 2 different salads
  • 5 different drinks

Let assume that the combo contains:  1 sandwich, 1 salad, and 1 drink

Hence, we have:

  • The total possible ways of choosing sandwiches she can choose is: 3
  • The total possible ways of choosing salads she can choose is: 2
  • The total possible ways of choosing drinks she can choose is: 5

=> Total ways = 3*5*2 = 30 ways or there are 30 different combos Keisha can choose

Hope it will find you well.

5 0
4 years ago
PLEASE HELP WITH THIS ONE AS WELL! I’m struggling with Transcendental Functions!
Svetach [21]

h(x)=20e^{kx}

a. If h(1)=20, then 20=20e^k\implies e^k=1\implies k=0.

b. If h(1)=40, then 40=20e^k\implies e^k=2\implies k=\ln2, so that 2k+1=2\ln2+1.

c. If h(1)=10, then 10=20e^k\implies e^k=\dfrac12\implies k=-\ln2, so that k-3=-\ln2-3.

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3 years ago
This question has two parts. Be sure to answer both parts of the question. One inequality in a system is shown below. -12x + 3y
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The inequality is -12x + 3y > 9.

PART A:

The sytem has no solution if inequality does not share a common area. The inequality -12x + 3y > 9 consist the region to left of line -12x + 3y = 9. So for no solution the region to left of equation -12x + 3y = 9 is suitable.

Thus inequality for no solution is, -12x + 3y < 9.

PART B:

For infinite solution the region of both inequality must overlap each other, or the inequality is same with some multiplication of divison factor. So inequality for infinite many solutions is,

\begin{gathered} (-12x+3y>9)\times-1 \\ 12x-3y

Thus inequality for infinite many solution is 12x - 3y < -9.

7 0
1 year ago
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