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4 years ago

11

PLEASE HELP!!! I NEED TO SUBMIT BY 12 AM AND I AM STUCK!

1 answer:

Veronika [31]4 years ago

4 0

Hope this helps! I can’t help with the graphing...

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What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

uysha [10]

Answer:

The perimeter of the trapezoid is $38.25\ units$

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

so

In this problem

$P=QR+RS+ST+QT$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$Q(8, 8), R(14, 16), S(20, 16),T(22, 8)$

step 1

Find the distance QR

$Q(8, 8), R(14, 16)$

substitute the values in the formula

$d=\sqrt{(16-8)^{2}+(14-8)^{2}}$

$d=\sqrt{(8)^{2}+(6)^{2}}$

$d=\sqrt{100}$

$QR=10\ units$

step 2

Find the distance RS

$R(14, 16), S(20, 16)$

substitute the values in the formula

$d=\sqrt{(16-16)^{2}+(20-14)^{2}}$

$d=\sqrt{(0)^{2}+(6)^{2}}$

$d=\sqrt{36}$

$RS=6\ units$

step 3

Find the distance ST

$S(20, 16),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-16)^{2}+(22-20)^{2}}$

$d=\sqrt{(-8)^{2}+(2)^{2}}$

$d=\sqrt{68}$

$ST=8.25\ units$

step 4

Find the distance QT

$Q(8, 8),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-8)^{2}+(22-8)^{2}}$

$d=\sqrt{(0)^{2}+(14)^{2}}$

$d=\sqrt{196}$

$QT=14\ units$

step 5

Find the perimeter

$P=10+6+8.25+14=38.25\ units$

6 0

3 years ago

Read 2 more answers

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QveST [7]

Answer 7

Explanation

you need to divide 63 by 9 to get 7

3 0

3 years ago

Which equation is equivalent to the equation below?

olasank [31]

The answer you are looking for is the letter i.
5n + 30 = 2n - 2

8 0

3 years ago

How to round 64781 in thousands

irina1246 [14]

Answer:

65000

Step-by-step explanation:

Just round the number

6 0

3 years ago

Two rectangular picture frames have the same area of 45 square inches but have different side lengths. Frame A has a length of 6

Vilka [71]

9514 1404 393

Answer:

1. the longer frame (B) has the shorter width

2. the shorter width is 6 3/7 inches, area divided by length

Step-by-step explanation:

The relation between area, length, and width is ...

A = LW

Then the width is ...

W = A/L . . . . . inversely proportional to length

__

1. Since length and width are inversely proportional (when area is constant), the shorter width will be associated with the longer length. Frame B will have the shorter width.

__

2. The width of frame B is ...

W = A/L = (45 in²)/(7 in) = 45/7 in = 6 3/7 in

5 0

3 years ago