Now despite what you may think, 1:3 is not 1/3 in this situation, but rather it's "1 equal part to 3 equal parts", which is a total of 4 equal parts. In short, they want the point that is at the 1/4 mark from A to B.

Firstly, how many units apart is 1 to 5 (the x-coordinates)? That would be 4 units apart. Multiply 1/4 by 4:

$\frac{1}{4}\times \frac{4}{1}=\frac{4}{4}=1$

Next, how many units apart is 2 to 3 (the y-coordinates)? That would be 1 unit apart. Multiply 1/4 by 1:

$\frac{1}{4}\times \frac{1}{1}=\frac{1}{4}$

Next, since from 1 to 5 you are increasing, add 1 to 1.

$1+1=2$

2 is the x-coordinate of the new point.

Next, since from 2 to 3 you are increasing, add 1/4 to 2.

$2+\frac{1}{4}=2\frac{1}{4}=\frac{9}{4}$

9/4 is the y-coordinate of the new point.

Putting it together, the point which divides AB into a 1:3 ratio is (2, 9/4), or D.

4 0

3 years ago

What is the absolute value of -2/2

Evgesh-ka [11]

-2/2 = -1/1 = -1

Therefore, the absolute value of -2/2 is -1.

6 0

3 years ago

Read 2 more answers

Whats the answer for (5x + 8)(4x² + 6x - 8)

mestny [16]

$(5x + 8)(4x^2 + 6x - 8)\\ \\ 5x(4x^2 + 6x - 8) + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 8(4x^2 + 6x - 8) \\ \\ 20x^3 + 30x^2 - 40x + 32x^2 + 48x - 64 \\ \\ 20x^3 + (30x^2 + 32x^2) + (-40x + 48x) - 64 \\ \\ 20x^3 + 62x^2 + 8x - 64 \\ \\$

The final result is: 20x^3 + 62x^2 + 8x - 64.

4 0

3 years ago

What is the area, in square centimeters, of the isosceles trapezoid below?

cluponka [151]

Answer:

The Area=122.4^2

7 0

2 years ago