Answer:
y=x/2-1/4
Step-by-step explanation:
From exercise we have
C=0.
dy/dx+2y=x
Use the formula:
∫xe^(2x)dx=e^(2x)(x/2−1/4).
We know that a linear differential equation is written in the standard form:
y' + a(x)y = f(x)
we get that: a(x)=2 and f(x)=x.
We know that the integrating factor is defined by the formula:
u(x)=e^{∫ a(x) dx}
⇒ u(x)=e^{∫ 2 dx} = e^{2x}
The general solution of the differential equation is in the form:
y=\frac{ ∫ u(x) f(x) dx +C}{u(x)}
⇒ y=\frac{ ∫ e^{2x}· x dx + 0}{e^{2x}}
y=\frac{e^{2x} (x/2-1/4)}{e^{2x}
y=x/2-1/4
<span>-2b^2 -3b+14=0
(-2b - 7)(b - 2) = 0
hope it helps</span>
I would love to help you with this question just send all of the possible answer choices such A,B,C,D answers.
so, the repairman charges $45 for each hour of work, and $44 for the parts, now the parts are obtained only once, so that's a one-time charge of 44 bucks, let's see how the hours go.
1 hour of work................... 45 + 44(1)
2 hours of work................45 + 44(2)
3 hours of work................45 + 44(3)
4 hours of work................45 + 44(4)
x hours of work................45 + 44(x)
so the cost equation, with x = hours, C(x) = 45 + 44x.
what is x if C(x) = 179?