The optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm
<h3><u>
Solution:</u></h3>
Given that,
<h3><u>The optimum diameter d (in millimeters) of the pinhole in a pinhole camera can be modeled by:</u></h3>
![d = 1.9[(5.5 \times 10^{-4})l]^{\frac{1}{2}}](https://tex.z-dn.net/?f=d%20%3D%201.9%5B%285.5%20%5Ctimes%2010%5E%7B-4%7D%29l%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
where l is the length (in millimeters) of the camera box
<h3><u>Find the optimum pinhole diameter for a camera box with a length of 10 centimeters</u></h3>
l = 10 cm
We know that,
10 cm = 100 mm
<em><u>Therefore, plug in l = 100 in given formula</u></em>
![d = 1.9[(5.5 \times 10^{-4}) \times 100]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-4} \times 10^2]^{\frac{1}{2}}\\\\d = 1.9[5.5 \times 10^{-2}]^{\frac{1}{2}}\\\\d = 1.9 \times 5.5^{\frac{1}{2} \times 10^{-1}}\\\\d = 0.19 \times 2.345207\\\\d = 0.4455 \approx 0.446](https://tex.z-dn.net/?f=d%20%3D%201.9%5B%285.5%20%5Ctimes%2010%5E%7B-4%7D%29%20%5Ctimes%20100%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%5B5.5%20%5Ctimes%2010%5E%7B-4%7D%20%5Ctimes%2010%5E2%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%5B5.5%20%5Ctimes%2010%5E%7B-2%7D%5D%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5Cd%20%3D%201.9%20%5Ctimes%205.5%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%5Ctimes%2010%5E%7B-1%7D%7D%5C%5C%5C%5Cd%20%3D%200.19%20%5Ctimes%202.345207%5C%5C%5C%5Cd%20%3D%200.4455%20%5Capprox%200.446)
Thus the optimum pinhole diameter for a camera box with a length of 10 centimeters is 0.446 mm
Answer:
25
Step-by-step explanation:
If you add 25 to both sides, you get
x^2-10x+25=26.
Now, you can simplify the left side into a perfect square
(x-5)^2=26
(x-6)(x-6)
Because this equals x² - 6x - 6x +36 which equals x²-12x+36
Subtract 2x from both sides.
3y = - 2x - 12
Divide every term by 3 to get the y-variable by itself.
y = - 2/3x - 4
Since the equation is not in slope-intercept form (y = mx + b), your y-intercept is just the number in the b slot. Y-intercept is - 4 or (0, - 4).
Now to find your x-intercept, plug in 0 where the y-variable is and solve for x.
0 = - 2/3x - 4
4 = - 2/3x
Multiply both sides by - 3/2 to isolate the variable.
4(- 3/2) = x
- 12/2 = x
- 6 = x.
Your x-intercept is - 6 or (- 6, 0).
Answer: 4.6 km
Step-by-step explanation:
a^1 + b^2 = c^2
2^2 + b^2 = 5^2
4 + b^2 = 25
b = sqrt 25 - 4
b = sqrt 21 = 4.6 km
