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ella [17]
3 years ago
7

A parking structure has three levels. There are 47 cars on the first level and 61 cars on the third level. How many cars are on

the second level?
Mathematics
1 answer:
Anestetic [448]3 years ago
7 0
54 I believe if this is what I think it is the end of the world as we see it the most hardest math riddle to have ever existed 61-47 = 14 
47+7=54  54+7= 61 therefore the world as we know shall come to a end at 2:08 PM Central time 
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Work the following area application problem.
Nookie1986 [14]

SInce you need 1.5 feet of overhang, add 3 feet to each axis dimension 1.5 on each side):

Minor Axis = 18 + 3 = 21 feet

Major axis = 25 + 3 = 28 feet


The area of an ellipse is found by multiplying half the minor axis by half the major axis by PI.


1/2 minor axis = 21 / 2 = 10.5

1/2 major axis = 28 / 2 = 14

Using 3.14 for PI

Area = 10.5 x 14 x 3.14 = 147 x 3.14 = 461.6 sq ft

7 0
3 years ago
Read 2 more answers
How many times does 81,000 goes into 8,000
Effectus [21]
Zero. That number cannot go into that one
8 0
2 years ago
Answer correctly please ASAP!
Serggg [28]

10 1/2 ft=2x-18 in

convert ft to in--10 1/2ft=126 in

126=2x-18

2x=144

x=<em>72 inches or 6 feet</em>

5 0
3 years ago
50pts PLEASE HURRY UP I WILL GIVE BRAINLEST SHOW ALL OF YOUR WORK ANSWER ALL THE QUESTIONS
blagie [28]

Answer:

In two spins, there are 9 possible outcomes:  AA, AB, AC, BA, BB, BC, CA, CB, CCIf we assume each of these is equally likely, then the probability of AB or BA is ...  2/9

Step-by-step explanation:

3 0
2 years ago
If the local linear approximation of f(x) = 2cos x + e^2x at x = 2 is used to find the approximation for f(2.1), then the % erro
yKpoI14uk [10]

<u>Answer-</u>

The % error of this approximation is 1.64%

<u>Solution-</u>

Here,

\Rightarrow f(x) = 2\cos x + e^{2x}

\Rightarrow f'(x) = -2\sin x + 2e^{2x}

And,

\Rightarrow f(2) = 2\cos 2 + e^{4}

\Rightarrow f'(2) = -2\sin 2 + 2e^{4}

Taking (2, f(2)) as a point and slope as, f'(2), the function would be,

\Rightarrow y-y_1=m(x-x_1)

\Rightarrow y-(2\cos 2 + e^{4})=(-2\sin 2 + 2e^{4})(x-2)

\Rightarrow y=(-2\sin 2 + 2e^{4})(x-2)+(2\cos 2 + e^{4})

The value of f(2.1) will be

\Rightarrow y=(-2\sin 2 + 2e^{4})(2.1-2)+(2\cos 2 + e^{4})

\Rightarrow y=(-2\sin 2 + 2e^{4})(0.1)+(2\cos 2 + e^{4})

\Rightarrow y=64.5946

According to given function, f(2.1) will be,

\Rightarrow f(2.1) = 2\cos 2.1 + e^{2(2.1)}

\Rightarrow f(2.1) = 65.6766

\therefore \%\ error=\dfrac{65.6766-64.5946}{65.6766}=0.0164=1.64\%

5 0
3 years ago
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