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Jlenok [28]
3 years ago
13

8 - 3/2b = 11 solve The equation. Check your solution

Mathematics
1 answer:
denis23 [38]3 years ago
8 0
B=-2, all of my steps and answer are listed in this pic
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Examine the power.
son4ous [18]
La respuesta es el número 4
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3 years ago
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Convert the angle theta=7/4pi radians to degrees
bagirrra123 [75]
7/4pi multiplied by 180/pi give you about 97 degrees when you calculate it.
7 0
3 years ago
10. Two lighthouses are located on a north-south line.
Kamila [148]

The question is an illustration of bearing (i.e. angles) and distance (i.e. lengths)

The distance between both lighthouses is 5783.96 m

I've added an attachment that represents the scenario.

From the attachment, we have:

\mathbf{\angle A = 180^o - 120^o\ 43'}

Convert to degrees

\mathbf{\angle A = 180^o - (120^o +\frac{43}{60}^o)}

\mathbf{\angle A = 180^o - (120^o +0.717^o)}

\mathbf{\angle A = 180^o - (120.717^o)}

\mathbf{\angle A = 59.283^o}

\mathbf{\angle B = 39^o43'}

Convert to degrees

\mathbf{\angle B = 39^o + \frac{43}{60}^o}

\mathbf{\angle B = 39^o + 0.717^o}

\mathbf{\angle B = 39.717^o}

So, the measure of angle S is:

\mathbf{\angle S = 180 - \angle A - \angle B} ---- Sum of angles in a triangle

\mathbf{\angle S = 180 - 59.283 - 39.717}

\mathbf{\angle S = 81}

The required distance is distance AB

This is calculated using the following sine formula:

\mathbf{\frac{AB}{\sin(S)} = \frac{AS}{\sin(B)} }

Where:

\mathbf{AS = 3742}

So, we have:

\mathbf{\frac{AB}{\sin(81)} = \frac{3742}{\sin(39.717)}}

Make AB the subject

\mathbf{AB= \frac{3742}{\sin(39.717)} \times \sin(81)}

\mathbf{AB= 5783.96}

Hence, the distance between both lighthouses is 5783.96 m

Read more about bearing and distance at:

brainly.com/question/19017345

5 0
2 years ago
20 ounces at $7 17 ounces at x dollars
tangare [24]
Make a proportion:
\frac{20}{7}  =  \frac{17}{x}
Then cross multiply and divide to solve.

20x=119

x=5.95

The answer is $5.95
6 0
3 years ago
Micah was asked to add the following expressions: 3x2−x−9x2+3x+2+−2x2+2x+5x2+3x+2 First, he combined like terms in the numerator
shtirl [24]

Micah was asked to add the following expressions:

\frac{3x^2-x-9}{x^2+3x+2} + \frac{-2x^2+2x+5}{x^2+3x+2}

First, he combined like terms in the numerator and kept the common denominator

First step is correct. He added the like terms in the numerator, because the denominators are same.

3x^2 -x -9 -2x^2+2x+5becomes x^2 +x -4

So he got , \frac{x^2+x-4}{x^2+3x+2}

In the next step, he cannot cancel out x^2 from the top and bottom . Because x-4 and 3x+2  are added with x^2

If we have x^2 is multiplied with other terms at the top and bottom , then we can cancel out x^2.

So Micah added the expression incorrectly. Final answer is not correct.

5 0
3 years ago
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