Answer:
The plasmid must express a gene for ampicillin resistance (the protein product of the <em>bla</em> gene codes for beta-lactamase, the protein that breaks down ampicillin). The colonies on the ampicillin plate are antibiotic resistant. This means that they have taken up the transformed plasmids expressing both the <em>bla</em> gene and the GFP gene.
Explanation:
The transformation involved the genetic modification of a plasmid to incorporate the gene encoding the green fluorescent protein (GFP) from jelly fish. GFP makes cells glow under UV light.
In genetic engineering, scientists use antibiotic resistance as markers to indicate cells that have been transformed. By incorporating an antibiotic resistance gene such as <em>bla</em> into the vector (plasmid) and then growing the cells in antibiotic media, scientists determine which colonies have taken up the plasmid. Therefore, if the cells survive, this means that they contain the plasmid with antibiotic resistance gene as well as the GFP gene.
Answer:
Granulosa cells
Explanation:
Foliculogenesis is a dynamic and complex process through which the follicle goes through many stages of development in a short period (approximately 60 days in humans and some chimpanzees).
The stages classification is based on morphological changes such as follicular size or diameter, the number of follicular cell layers, etcetera. These classifications might vary among authors but could be denominated as:
- De Graaf follicles (This is the one shown in the image)
Through each stage, there are certain modifications in the oocyte, follicular cells, and connective tissue. As the oocyte grows, the follicular cells might reach a size twice or three times bigger than the ones of the primordial follicles. Their shape also changes and they adopt an aspect of stratified epithelium. Their cytoplasm gets a granulous aspect, after what these cells receive the name of <u><em>granulous cells</em></u>. The De Graaf follicle characterizes for having a space named follicular antro that displaces the oocyte to one of the sides.
The oocyte at this point gets surrounded by <u>zona pellucida</u> and <u>corona radiata </u>.
The follicular antro (The highlighted structure) separates the oocyte from the externally located <u>granulosa cells</u> or follicular cells.
Answer:
In eukaryotes, it is well known that polyadenylation is required to produce the mature messenger RNA (mRNA) molecule and it provides stability to the mRNA during translation initiation. In prokaryotic organisms, polyadenylation is required for the degradation of the mRNA in a mechanism that involves three steps: endonucleolytic cleavage, polyadenylation and exonucleolytic degradation. Moreover, it is also important to note that no evidence of polyadenylation has bee reported in some prokaryotes including the halophilic bacteria Haloferax volcanic (Slomovic et al. 2005).
Citation:
Slomovic, S., Laufer, D., Geiger, D., & Schuster, G. (2005). Polyadenylation and degradation of human mitochondrial RNA: the prokaryotic past leaves its mark. Molecular and cellular biology, 25(15), 6427-6435.
The viral capsid and envelope <span>plays a role in attaching a virion to the host cell.</span>
If a person skipped lunch is could cause a low blood sugar
level and this will likely affect the liver cells in having it to react in
which glycogenolysis occurs. This process in the liver cells is a way of
breaking down glycogen in a way to fuel the body as it turns into glucose.
