Answer:
240 square inches
Step-by-step explanation:
1 foot = 12 inches
to convert 4/3 ft to inches, multiply by 12
4/3 × 12 = 16 inches
the area of a square = base × height
base = 16, height = 15
16 × 15 = 240 square inches
Answer:
Step-by-step explanation:
A fixed pulley consists of a wheel fixed to a shaft and is used in conjunction with a belt to transfer energy to another fixed pulley. A movable pulley consists of a shell, a movable wheel and a rope. Movable pulleys are also know as block and tackle.
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I = ![\frac{1}{2}(\text{Base})\times (\text{Height})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BBase%7D%29%5Ctimes%20%28%5Ctext%7BHeight%7D%29)
Area of ΔADC = ![\frac{1}{2}(\text{CD})(\text{AD})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BCD%7D%29%28%5Ctext%7BAD%7D%29)
= ![\frac{1}{2}(\sqrt{(AC)^2-(AD)^2})(\text{AD})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Csqrt%7B%28AC%29%5E2-%28AD%29%5E2%7D%29%28%5Ctext%7BAD%7D%29)
= ![\frac{1}{2}(\sqrt{(13)^2-(19-7)^2} )(19-7)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Csqrt%7B%2813%29%5E2-%2819-7%29%5E2%7D%20%29%2819-7%29)
= ![\frac{1}{2}(\sqrt{169-144})(12)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Csqrt%7B169-144%7D%29%2812%29)
= ![\frac{1}{2}(5)(12)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%285%29%2812%29)
= 30 cm²
Area of equilateral triangle II = ![\frac{\sqrt{3} }{4}(\text{Side})^2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B4%7D%28%5Ctext%7BSide%7D%29%5E2)
Area of equilateral triangle II = ![\frac{\sqrt{3}}{4}(13)^2](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%2813%29%5E2)
= ![\frac{(1.73)(169)}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B%281.73%29%28169%29%7D%7B4%7D)
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH = ![\frac{1}{2}(\text{EF}+\text{GH})(\text{FJ})](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28%5Ctext%7BEF%7D%2B%5Ctext%7BGH%7D%29%28%5Ctext%7BFJ%7D%29)
Since, GH = GJ + JK + KH
17 = ![\sqrt{9^{2}-x^{2}}+5+\sqrt{(15)^2-x^{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B9%5E%7B2%7D-x%5E%7B2%7D%7D%2B5%2B%5Csqrt%7B%2815%29%5E2-x%5E%7B2%7D%7D)
12 = ![\sqrt{81-x^2}+\sqrt{225-x^2}](https://tex.z-dn.net/?f=%5Csqrt%7B81-x%5E2%7D%2B%5Csqrt%7B225-x%5E2%7D)
144 = (81 - x²) + (225 - x²) + 2![\sqrt{(81-x^2)(225-x^2)}](https://tex.z-dn.net/?f=%5Csqrt%7B%2881-x%5E2%29%28225-x%5E2%29%7D)
144 - 306 = -2x² + ![2\sqrt{(81-x^2)(225-x^2)}](https://tex.z-dn.net/?f=2%5Csqrt%7B%2881-x%5E2%29%28225-x%5E2%29%7D)
-81 = -x² + ![\sqrt{(81-x^2)(225-x^2)}](https://tex.z-dn.net/?f=%5Csqrt%7B%2881-x%5E2%29%28225-x%5E2%29%7D)
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV = ![\frac{1}{2}(5+17)(9)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%285%2B17%29%289%29)
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²
Answer:
2400 words
Step-by-step explanation:
80 = 2 min
60min ÷ 2min = 30min
30 × 80 = 2400 words