In geometry, a median of a triangle is a line segment joining a vertex to the midpoint of the opposite side, thus bisecting that side. Every triangle has exactly three medians, one from each vertex, and they all intersect each other at the triangle's centroid.

3 0

4 years ago

Solve for x. HELPPP MEEEE PLEASE

Elina [12.6K]

Answer:

Step-by-step explanation:

5 0

3 years ago

Sharon bought 6 new folders for $1.15 each and 15 pens that were priced at 5 for $4.75. What is the total amount she spent?

inessss [21]

Answer:

$21.15

Step-by-step explanation:

6 x 1.15 = 6.9 (because we're working with money, we'll add a zero at the end for the ones place) = 6.90

15/5 = 3 then 3 x 4.75= 14.25

14.25 + 6.90 = 21.15

Hope this helped <3

6 0

3 years ago

Read 2 more answers

X^2-8x+16=5 what are the solutions?

svp [43]

Hey!

The first step to solving this equation would be to subtract 5 from both sides of the equation.

Original Equation :
$x^{2}$ - 8x + 16 = 5

New Equation {Added Subtract 5 to Both Sides} :
$x^{2}$ - 8x + 16 - 5 = 5 - 5

Now we solve our new equation.

Old Equation :
$x^{2}$ - 8x + 16 - 5 = 5 - 5

Solution {Old Equation Solved} :
$x^{2}$ - 8x + 11 = 0

The next step would be to solve with the quadratic formula.

Quadratic Equation ( 1 ) :
$x = \frac{-(-8) + \sqrt{(-8)^{2} -4 * 1 * 11 } }{2*1}$

Quadratic Equation ( 1 ) {Solved} :
4 + $\sqrt{5}$

Quadratic Equation ( 2 ) :
$x = \frac{-(-8) - \sqrt{(-8)^{2}-4 *1*11 } }{2*1}$

Quadratic Equation ( 2 ) {Solved} :
4 - $\sqrt{5}$

So, our final solutions for the equation $x^{2}$ - 8x + 16 = 5 are...

x = 4 + $\sqrt{5}$

and 

x = 4 - $\sqrt{5}$

Hope this helps!

- Lindsey Frazier ♥

5 0

4 years ago