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2 years ago

6

Sharon bought 100/300/100 policy with a $100 deductible on collision and $100 deductible on comprehensive coverage.

1 answer:

Ronch [10]2 years ago

8 0

The answer would be 1,928.85

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Determine the midpoint between the points (-5, 3) and (5, 9).

PSYCHO15rus [73]

Answer:

M (0, 6)

Step-by-step explanation:

By midpoint formula,

M [(x1+x2)/2 , (y1+y2)/2]

M [-5+5/2 , 3+9/2]

M (0/2 , 12/2)

M (0, 6)

4 0

1 year ago

A present is shaped like a

matrenka [14]

Answer: Yes

Step-by-step explanation:

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3 years ago

For each of the following vector fields

olga nikolaevna [1]

(A)

$\dfrac{\partial f}{\partial x}=-16x+2y$

$\implies f(x,y)=-8x^2+2xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=10y$

$\implies g(y)=5y^2+C$

$\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}$

(B)

$\dfrac{\partial f}{\partial x}=-8y$

$\implies f(x,y)=-8xy+g(y)$

$\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x$

$\implies \dfrac{\mathrm dg}{\mathrm dy}=x$

But we assume $g(y)$ is a function of $y$ alone, so there is not potential function here.

(C)

$\dfrac{\partial f}{\partial x}=-8\sin y$

$\implies f(x,y)=-8x\sin y+g(x,y)$

$\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y$

$\implies\dfrac{\mathrm dg}{\mathrm dy}=4y$

$\implies g(y)=2y^2+C$

$\implies f(x,y)=\boxed{-8x\sin y+2y^2+C}$

For (A) and (C), we have $f(0,0)=0$ , which makes $C=0$ for both.

4 0

2 years ago

Adam is rewriting the expression 8^5/8^2

zhuklara [117]

Answer:

8^3

Step-by-step explanation:

3 0

3 years ago

Identify the equation in slope-intercept form for the line containing the point (−3,5) and parallel to y=−2/3x+53.

Alexeev081 [22]

Answer:

y=−2/3x+3

Step-by-step explanation:

I graphed the point and the equation given below. I used the same slope in the new equation as the original equation. The y-intercept is 3 because the line goes through (0,3).

3 0

3 years ago