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4 years ago

What Is the Slope And Y Intercept Of This Line? Y = X -5

Mathematics

1 answer:

asambeis [7]4 years ago

6 0

Answer:

slope = 1 , y- intercept = - 5

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = x - 5 is in this form

with slope m = 1 and y- intercept c = - 5

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40x-25 y = 180 Solve for x and y

Lostsunrise [7]

Answer:

5 /8y+9/2

Step-by-step explanation:

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3 years ago

In the metric system, multiplying by 1000 would be the same as moving the decimal point _____ place(s) to the right.

hodyreva [135]

It would be the same as moving the decimal three to the right, and that applies to everything, not just the metric system.

3 0

3 years ago

Read 2 more answers

Please help. Solve the triangle. Round ans to the nearest tenth.

White raven [17]

9514 1404 393

Answer:

C = 21°
a = 13.3
c = 5.4

Step-by-step explanation:

The third angle can be found from the sum of angles in a triangle.

A + B + C = 180°

C = 180° -62° -97°

C = 21°

The remaining side lengths can be found using the Law of Sines.

a/sin(A) = b/sin(B)

a = sin(62°)(15/sin(97°)) ≈ 13.34

Similarly, ...

c/sin(C) = b/sin(B)

c = sin(21°)(15/sin(97°)) ≈ 5.42

The remaining side lengths are approximately ...

a ≈ 13.3

c ≈ 5.4

4 0

3 years ago

Need some help, please. What do I plot? I attempted to figure the questions out many times, but I've come to no clear conclusion

olganol [36]

Answer:

vertex is (4,-4) and another point is (6,0) or you could use (2,0) or many other options :)

Step-by-step explanation:

The cool thing about this question your quadratic is in factored form so your x-intercepts are easy to figure out, they are 2 and 6.

So you can plot (6,0) and (2,0).

The vertex will lie half between x=2 and x=6... so it lays at (6+2)/2=4

We just have to find the y-coordinate for when x=4.

Plug in 4 gives you (4-2)(4-6)=(2)(-2)=-4.

So the vertex is at (4,-4).

5 0

4 years ago

let a = (a1, a2) and b = (b1, b2) and c = (c1,c2) be three non zero vectors. if a1b2 - a2b1 is not equal to 0. then show three a

Ksenya-84 [330]

Consider the contrapositive of the statement you want to prove.

The contrapositive of the logical statement

p ⇒ q

¬q ⇒ ¬p

In this case, the contrapositive claims that

"If there are no scalars α and β such that c = αa + βb, then a₁b₂ - a₂b₁ = 0."

The first equation is captured by a system of linear equations,

$\begin{cases}c_1 = \alpha a_1 + \beta b_1\\ c_2 = \alpha a_2 + \beta b_2\end{cases}$

or in matrix form,

$\begin{pmatrix}c_1\\c_2\end{pmatrix} = \begin{pmatrix}a_1&b_1\\a_2&b_2\end{pmatrix}\begin{pmatrix}\alpha\\\beta\end{pmatrix}$

If this system has no solution, then the coefficient matrix on the right side must be singular and its determinant would be

$\begin{vmatrix}a_1&b_1\\a_2&b_2\end{vmatrix} = a_1b_2-a_2b_1 = 0$

and this is what we wanted to prove. QED

3 0

3 years ago