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marin [14]
3 years ago
10

What Is the Slope And Y Intercept Of This Line? Y = X -5

Mathematics
1 answer:
asambeis [7]3 years ago
6 0

Answer:

slope = 1 , y- intercept = - 5

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = x - 5 is in this form

with slope m = 1 and y- intercept c = - 5


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Determime the measures of angles X,y and Z
Ierofanga [76]

Answer:

X = 75°

Y = 105°

Z =75

Step-by-step explanation:

8 0
3 years ago
V^2+2=8-4v^2 solve the question algebically
iris [78.8K]

Answer:

v =  ± sqrt(6/5)

Step-by-step explanation:

v^2+2=8-4v^2

Add 4v^2 to each side

v^2+ 4v^2+2=8-4v^2+ 4v^2

5v^2 +2 = 8

Subtract 2 from each side

5v^2  +2-2 = 8-2

5 v^2 = 6

Divide each side by 5

5v^2 /5 = 6/5

v^2 = 6/5

Take the square root of each side

sqrt(v^2)  = ± sqrt(6/5)

v =  ± sqrt(6/5)

8 0
3 years ago
Read 2 more answers
We are given that m∠AEB = 45° and ∠AEC is a right angle. The measure of ∠AEC is 90° by the definition of a right angle. Applying
melomori [17]

Answer:

The proof is given below.

Step-by-step explanation:

Given m∠AEB = 45° and ∠AEC is a right angle. we have to prove that EB divides ∠AEC into two congruent angles, it is the angle bisector.

Given ∠AEC=90°      (Given)

∠AEC=∠AEB+∠BEC  

⇒ 90° = 45° +∠BEC      (Substitution Property)

By subtraction property of equality

⇒ ∠BEC = 90° - 45° = 45°    

Hence, both angles becomes equal gives ∠AEB≅∠BEC

Since EB divides ∠AEC into two congruent angles, ∴ EB is the angle bisector.


5 0
3 years ago
Read 2 more answers
Let f(x)=5e^3x and g(x)=2/3ln(5x); find (f(g))(2)
Sedbober [7]

Answer:

<h2>a) 500</h2>

Step-by-step explanation:

(f\circ g)(x)=f\bigg(g(x)\bigg)\\\\(f\circ g)(2)=f\bigg(g(2)\bigg)\\\\f(x)=5e^{3x},\ g(x)=\dfrac{2}{3}\ln(5x)\\\\(f\circ g)(x)\to\text{in}\ f(x)\ \text{replace}\ x\ \text{with the expression}\ \dfrac{2}{3}\ln(5x):\\\\(f\circ g)(x)=5e^{3\cdot\frac{2}{3}\ln(5x)}=5e^{2\ln(5x)}\qquad\text{use}\ \ln a^n=n\ln a\\\\(f\circ g)(x)=5e^{\ln(5x)^2}\qquad\text{use}\ a^{\log_ab}=b\\\\(f\circ g)(x)=5(5x)^2=5(5^2x^2)=5(25x^2)=125x^2\\\\(f\circ g)(2)\to\text{put}\ x=2\\\\(f\circ g)(2)=125(2^2)=125(4)=500

3 0
2 years ago
Multiply the monomials:<br> -11x^2y and 0.3x^2y^3
ANEK [815]

Answer:

-3.3x^4y^4

Step-by-step explanation:

-11x^2y and 0.3x^2y^3

-11x^2y * 0.3x^2y^3

Multiply the constants

-11 * .3 = -3.3

Multiply the x terms

We know that a^b*a^c = a^(b+c)

x^2 * x^2 = x^(2+2) = x^2

Multiply the y terms

y * y^3 = y^(1+3) = y^4

Put them all together

-3.3x^4y^4

5 0
3 years ago
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