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Bess [88]
3 years ago
11

Find the slope for each pair of points. (-2,5), (3,-4) help plssss

Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0
The answer would be -26
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Steve has at most $80 to spend at a store. He wants to buy a movie that costs $22. He also wants to buy DVDs that cost $7.00 eac
Degger [83]

Answer:

80 is less than or equal to 22+7x

8 DVDs

Step-by-step explanation:

I don't have the inequality signs sorry if you don't know its the symbol thats opening to the left with a line underneath

80 is less than or equal to 22+7x

subtract 22

58 is less than or equal to 7x

divide and flip the sign to the right

x is greater than or equal to 8.29

so he can buy 8 DVDs in total

5 0
3 years ago
Which of the following numbers has an odd number of factors 13,15,25,26?
kvv77 [185]

Answer:

25. Its cubed.

Step-by-step explanation:

7 0
3 years ago
At what value of x does the graph of the following function F(x) have a
Free_Kalibri [48]

Answer:

B

Step-by-step explanation:

Given

f(x) = \frac{1}{x+2}

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 2 = 0 ⇒ x = - 2

The equation of the vertical asymptote is x = - 2

6 0
3 years ago
Math question with a screenshot. Brainliest will be rewarded for the best answer.
Law Incorporation [45]
So So sorry, I answered so late xd

The mean can be found by adding all the numbers then dividing it by the amount of numbers

The mean for team A is about 7.7 
and the mean for team B is about 7.6
So they're A.) About the same

To find the range find the biggest number then subtract it by the smallest
Team A: 12,0 ; 12 - 0 = 12
12 is the range
Team B: 12,3 ; 12 - 3 = 9
The answer is B.) <span>much greater for conference a than for b</span>
6 0
3 years ago
Read 2 more answers
Find the value of x and y if 50=x+y
solong [7]
180-50=130
x-y=130
x+y=50
2x=180
x=90
90+y=50
y=50-90
y=-40
6 0
3 years ago
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