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murzikaleks [220]
3 years ago
7

HEEEEEEEEEEEELELLLLLELEP PLEASE ;)

Mathematics
1 answer:
Readme [11.4K]3 years ago
6 0

When you divide a number by 10^n (i.e. 1 followed by n zeroes), you move the decimal point separator n places to the left (assuming that integers have the decimal separator at the end, as in 2 = 2.0).

So, the first option is to divide 18 by 100. So, we start from 18=18.0 and move the separator two places to the left:

18 \to 0.18

The second option is to divide 8 by 10. So, we start from 8=8.0 and move the separator one place to the left:

8 \to 0.8

The third option is to divide 18 by 10. So, we start from 18=18.0 and move the separator one place to the left:

18 \to 1.8

So this is the correct option.

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A class votes for their class President Kennedy receives 21 votes which is 6% of the vote what is the total number of students w
Katarina [22]

Answer:

21

Step-by-step explanation:

literally says it in the text ight

6 0
2 years ago
Read 2 more answers
Given: 5n - 42 = 12n; Prove: n= -6<br> What are the Statements<br> What are the Reasons
asambeis [7]

Answer:

-72=-72

Step-by-step explanation:

5n-42=12n

n=-6

5*(-6)-42 = 12*(-6)

-30-42=-72

-72=-72

So, n= -6 is the right number for this equation

4 0
2 years ago
Write down how you skip-count by ten from 350 to 240
Mamont248 [21]

Answer: 350,340,330,320,310,300,290,280,270,260,250,240.


Step-by-step explanation:

To solve this exercise you must keep on mind the following information:

1. By definition skip counting is about counting by a number which is not the number 1.

2. Skip counting by ten from 350 to 240 means that you need to subtract 10 to a number to find the other one.

3. Therefore, you must subtract 10 to 350 and then you need to do this over and over again until you get 240.

7 0
2 years ago
This is a geometry question, i need something quickly :)
Marysya12 [62]

Answer:

hope it helps mark me brainlieast!

Step-by-step explanation:

<em>For triangle ABC with sides  a,b,c  labeled in the usual way, </em>

<em> </em>

<em>c2=a2+b2−2abcosC  </em>

<em> </em>

<em>We can easily solve for angle  C . </em>

<em> </em>

<em>2abcosC=a2+b2−c2  </em>

<em> </em>

<em>cosC=a2+b2−c22ab  </em>

<em> </em>

<em>C=arccosa2+b2−c22ab  </em>

<em> </em>

<em>That’s the formula for getting the angle of a triangle from its sides. </em>

<em> </em>

<em>The Law of Cosines has no exceptions and ambiguities, unlike many other trig formulas. Each possible value for a cosine maps uniquely to a triangle angle, and vice versa, a true bijection between cosines and triangle angles. Increasing cosines corresponds to smaller angles. </em>

<em> </em>

<em>−1≤cosC≤1  </em>

<em> </em>

<em>0∘≤C≤180∘  </em>

<em> </em>

<em>We needed to include the degenerate triangle angles,  0∘  and  180∘,  among the triangle angles to capture the full range of the cosine. Degenerate triangles aren’t triangles, but they do correspond to a valid configuration of three points, namely three collinear points. </em>

<em> </em>

<em>The Law of Cosines, together with  sin2θ+cos2θ=1 , is all we need to derive most of trigonometry.  C=90∘  gives the Pythagorean Theorem;  C=0  and  C=180∘  give the foundational but often unnamed Segment Addition Theorem, and the Law of Sines is in there as well, which I’ll leave for you to find, just a few steps from  cosC=  … above. (Hint: the Law of Cosines applies to all three angles in a triangle.) </em>

<em> </em>

<em>The Triangle Angle Sum Theorem,  A+B+C=180∘ , is a bit hard to tease out. Substituting the Law of Sines into the Law of Cosines we get the very cool </em>

<em> </em>

<em>2sinAsinBcosC=sin2A+sin2B−sin2C  </em>

<em> </em>

<em>Showing that’s the same as  A+B+C=180∘  is a challenge I’ll leave for you. </em>

<em> </em>

<em>In Rational Trigonometry instead of angle we use spreads, squared sines, and the squared form of the formula we just found is the Triple Spread Formula, </em>

<em> </em>

<em>4sin2Asin2B(1−sin2C)=(sin2A+sin2B−sin2C)2  </em>

<em> </em>

<em>true precisely when  ±A±B±C=180∘k , integer  k,  for some  k  and combination of signs. </em>

<em> </em>

<em>This is written in RT in an inverted notation, for triangle  abc  with vertices little  a,b,c  which we conflate with spreads  a,b,c,  </em>

<em> </em>

<em>(a+b−c)2=4ab(1−c)  </em>

<em> </em>

<em>Very tidy. It’s an often challenging third degree equation to find the spreads corresponding to angles that add to  180∘  or zero, but it’s a whole lot cleaner than the trip through the transcendental tunnel and back, which almost inevitably forces approximation.</em>

6 0
2 years ago
Can someone please help me answer this??
rewona [7]
<h3>Answer:  x = (y-2)^2 + 5</h3>

In other words, y-2 goes in the first box and 5 goes in the second box.

=================================================

Work Shown:

y^2 - 4y - x + 9 = 0

y^2 - 4y + 9  = x

x = y^2 - 4y + 9

x = y^2 - 4y + 4 + 5 .... rewrite 9 as 4+5

x = (y^2-4y+4) + 5

x = (y-2)^2 + 5  .... apply the perfect square factoring rule

So we'll have y-2 go in the first box and 5 goes in the second box

note: One version of the perfect square factoring rule says (a-b)^2 = a^2-2ab+b^2.

4 0
2 years ago
Read 2 more answers
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