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vivado [14]
3 years ago
7

Somebody plz help me and If u can help me more plz help me on the rest too

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0

Answer:

it b

Step-by-step explanation:

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An adult soccer league requires a ratio of at least 2 women per 7 men on the roster. If 14 men are on the roster, how many women
Snezhnost [94]

Answer:

Atleast 4 women

Step-by-step explanation:

Ratio of

Women to men = 2 : 7

Number of women needed to maintain the ratio if there are 14 men on the roster :

The minimum number of women required :

(2 : 7) * number of men in roster

(2 / 7) * 14

2 * 2 = 4 women

Atleast 4 women are required to main the ratio

7 0
3 years ago
Which of the following is a point-slope equation for a line with the point (-2,4) and a slope of 3?
Sindrei [870]

Answer:

work is shown and pictured

4 0
3 years ago
ILL GIVE BRAINLEIST <br><br> Options: <br><br> 1. 40<br> 2. 50<br> 3. 80<br> 4. 100
schepotkina [342]

Answer: I would probably say c 80

Step-by-step explanation:

3 0
3 years ago
How can I use Pythagorean theorem to find g &amp; h ?
jasenka [17]
H^2+g^2=6^2
basically square each thing, and add h and g together
4 0
3 years ago
Giving brainliest!!!!!!!!!!!!!!!!!!!!!!!!!
GarryVolchara [31]

Answer: \pm1,\pm3,\pm5, \pm15

Step-by-step explanation:

We can list the possible rational roots of this polynomial using the Rational Root Theorem. This theorem states that all the possible rational roots of an equation follow the structure \frac{p}{q}, where <u>p is any of the factors of the constant term and q is any of the factors of the leading coefficient</u>.

In this example, -15 is the constant term and 1 is the leading coefficient (x^4 has a coefficient of 1).

The factors of -15 are \pm1,\pm3,\pm5, \pm15, while the factors of 1 are \pm1. <em>p </em>is can be any one of the factors of -15, while <em>q</em> can be any of the factors of 1.

\frac{\pm1,\pm3,\pm5, \pm15}{\pm1}

The possible roots can be any of the numbers on the top divided by any of the numbers on the bottom. Since dividing by 1 or -1 won't change any of the numbers on the top, the rational roots of this function are \pm1,\pm3,\pm5, \pm15.

3 0
2 years ago
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