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3 years ago

Can someone help me with this one

Mathematics

1 answer:

konstantin123 [22]3 years ago

6 0

Left 3, and the right 2

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I need help asap!! I don't really get it bc I don't know if you include the $12 or not.

olganol [36]

Yea so you include $12 for him getting in the clinic and then 30-12=18
And divide 3 and 18
So 6!

So he can have 6 buckets!

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3 years ago

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In triangle RST, RS = 6 cm, ST = 7 cm, and RT = 8 cm. What is the approximate measure of the largest angle in the triangle?

zubka84 [21]

the approximate measure of the largest angle in the triangle is 75.5 degrees

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3 years ago

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Please help! Giving brainliest!

lana66690 [7]

Answer:

Step-by-step explanation:

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2 years ago

A bird sees a worm on the ground 50 m. below. The bird dives for the worm at a speed of 6 m/sec. The function h\left( t \right)

iragen [17]

Given:

The height of the bird at time t is given by the function $h(t)=-4.9t^2+6t+50$

We need to determine the time it takes the worm to be eaten by the bird.

Time taken:

The time can be determined by substituting h(t) = 0 in the function.

Thus, we have;

$0=-4.9t^2+6t+50$

Switch sides, we get;

$-4.9t^2+6t+50=0$

Let us solve the equation using the quadratic formula.

Thus, we get;

$t=\frac{-6 \pm \sqrt{6^{2}-4(-4.9) 50}}{2(-4.9)}$

Simplifying, we get;

$t=\frac{-6 \pm \sqrt{36+980}}{-9.8}$

$t=\frac{-6 \pm \sqrt{1016}}{-9.8}$

$t=\frac{-6 \pm 31.87}{-9.8}$

The values of t are given by

$t=\frac{-6 + 31.87}{-9.8}$ and $t=\frac{-6 - 31.87}{-9.8}$

$t=\frac{25.87}{-9.8}$ and $t=\frac{-37.87}{-9.8}$

$t=-2.4$ and $t=3.9$

Since, the value of t cannot be negative, then $t=3.9$

Thus, the time taken by the bird to eat the worm is $t=3.9$ seconds.

Hence, Option B is the correct answer.

5 0

3 years ago

Give the following number in Base 16 NO LINKS!!!

olga nikolaevna [1]

Answer:

$\large{\boxed{35_{10} = \sf 23_{16}}}$

Explanation:

$\sf Given : 35_{10}$

Compute:

35 ÷ 16 = 2.1875 = 2R3

2 ÷ 16 = 0.125 = 0R2

Jot down the remainders:

3 ↑

2 ↑

======

$\sf Answer : \ 35_{10} = 23_{16}$

$\hrulefill$

Let's look at another example: $\sf 325_{10} = [?]_{16}$

Compute:

325 ÷ 16 = 20.3125 = 20R5

20 ÷ 16 = 1.25 = 1R4

1 ÷ 16 = 0.0625 = 0R1

Jot down remainders:

5 ↑

4 ↑

1 ↑

=====

$\sf 325_{10} = [145]_{16}$

$\hrulefill$

Another example: $\sf 500_{10} = [?]_{15}$

Compute:

500 ÷ 15 = 33.33... = 33R5

33 ÷ 15 = 2.2 = 2R3

2 ÷ 15 = 0.13... = 0R2

Jot down remainders:

5 ↑

3 ↑

2 ↑

=====

$\sf 500_{10} = [235]_{15}$

7 0

2 years ago