Can someone help me with this one

A ball is kicked in the air. The height of the ball can be calculated using the equation h(t) =-16t^2+64t+190, where h is in hei

gregori [183]

Answer:

Therefore the ball strikes the ground 5.98 s after kick.

Step-by-step explanation:

Given that , a ball is kicked in the air. The height of the ball can be calculated using the equation $h(t)=-16t^2+64t+190$ where h is height in feet and t is time in second.

When the ball touches the ground then the height will be zero.

i.e h(t)=0

Therefore

$-16t^2+64t+190=0$

$\Rightarrow -2(8t^2-32t-95)=0$

Since -2≠0 then $(8t^2-32t-95)=0$

$(8t^2-32t-95)=0$

[The solution of a quadratic equation ax²+bx+c=0 is

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$ here a=8, b=-32 and c=-95]

$\Rightarrow t =\frac{-(-32)\pm\sqrt{(-32)^2-[4\times8\times(-95)]} }{2\times8}$

$\Rightarrow t =\frac{32\pm\sqrt{4064} }{16}$

Therefore t= 5.98 or -1.98

since time can not be negative So , t=5.98 s

Therefore the ball strikes the ground 5.98 s after kick.

5 0

3 years ago

the cost of an annual tuition at a university increased from 10,500 to 11,300 what is the percent increase in tuition to the nea

Maurinko [17]

Percent increase
find increase first
10500 to 11300
11300-10500=800
so
percent increase
change/original
origianal=10500
change=800
800/10500=8/105=0.0761
percent means parts out of 100
0.0761/1 times 100/100=7.61/100=7.61%

rond 7.61% to tenth or to 7.6%

7.6%

5 0

3 years ago

19. 4x-y+2z = 8x+y-4 Find x

Varvara68 [4.7K]

Answer:

x = $\frac{4-2y+2z}{4}$