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NISA [10]
3 years ago
14

Please help me quickly

Mathematics
1 answer:
s2008m [1.1K]3 years ago
3 0
A function is defined as a set of points for every x-value, there is only one y-value.
So, you can't have two y-values for every x-value.

Thus, (B) would be a relation, because x = 7 has two y-values, and as such, doesn't satisfy the condition of a function.
You might be interested in
Given the geometric sequence where a1=1 and the common ratio is 6, what is the domain for n?​
kari74 [83]

We have been given that a geometric sequence's 1st term is equal to 1 and the common ratio is 6. We are asked to find the domain for n.

We know that a geometric sequence is in form a_n=a_1(r)^{n-1}, where,

a_n = nth term of sequence,

a_1 = 1st term of sequence,

r = Common ratio,

n = Number of terms in a sequence.

Upon substituting our given values in geometric sequence formula, we will get:

a_n=1\cdot (7)^{n-1}

Our sequence is defined for all integers such that n is greater than or equal to 1.

Therefore, domain for n is all integers, where n\geq 1.

4 0
3 years ago
3(x-7)+8=-20<br><br><br><br>can someone explain how to do this step by step​
Mrrafil [7]

3(x-7)+8=-20

Multiply the bracket by 3

(3)(x)(3(-7)+8= -20

3x-21+8= -20

3x-13= -20

Move -13 to the other side. Sign changes from -13 to +13.

3x-13+13= -20+13

3x= -7

Divide by 3

3x/3= -7/3

x= -7/3 or in mixed number : -2 1/3

Answer : x= -7/3 or in mixed number : -2 1/3

3 0
3 years ago
Read 2 more answers
Use powers to rewrite these problems: Example: 5 x 5 = 52
jeyben [28]

Answer:

<u>Problem A</u>

5 * 5 * x * x * x

5^2*x^3

<u>Problem B</u>

8 * 8 * 8

8^3

<u>Problem C</u>

4 * 4 * 4 * x * x * x * x

4^3*x^4

5 0
2 years ago
When calculating for volume, you use the area of the 2D shape. <br><br> True or false.
Nana76 [90]

Answer:

I think true.

Step-by-step explanation:

Whereas the basic formula for the area of a rectangular shape is length × width, the basic formula for volume is length × width × height.

5 0
3 years ago
Read 2 more answers
What is the radius of a circle whose equation is x^2+y^2-10x+6y + 18=0
rjkz [21]

Answer:

Explanation:

We must write this equation in the form

(

x

−

a

)

2

+

(

y

−

b

)

2

=

r

2

Where

(

a

,

b

)

are the co ordinates of the center of the circle and the radius is

r

.

So the equation is

x

2

+

y

2

−

10

x

+

6

y

+

18

=

0

Complete the squares so add 25 on both sides of the equation

x

2

+

y

2

−

10

x

+

25

+

6

y

+

18

=

0

+

25

=

(

x

−

5

)

2

+

y

2

+

6

y

+

18

=

0

+

25

Now add 9 on both sides

(

x

−

5

)

2

+

y

2

+

6

y

+

18

+

9

=

0

+

25

+

9

=

(

x

−

5

)

2

+

(

y

+

3

)

2

+

18

=

0

+

25

+

9

This becomes

(

x

−

5

)

2

+

(

y

+

3

)

2

=

16

So we can see that the centre is

(

5

,

−

3

)

and the radius is

√

16

or 4

6 0
3 years ago
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