So you can actually use a couple trig identities
tan(x-a) =(tan x-tan a)/(1+tan x*tan a)
From there, easy!
(tan x-tan a)/(tan x-tan a)/(1+tan x*tan a)
1/1/(1+tan x*tan a)
which is
(1+tanx*tana)
1+tan^2a
sec^2 a
typo, forgot the 1/1
Answer:
I think it is C-D.
Step-by-step explanation:
Answer:
5/6
Step-by-step explanation: