(a) m<IJK = 90 since segment IK is a diameter
(b) KI = 10 since since LM = KM = KI = 5. The 3 segments are radii.
(c) EP * PL = OP * PF; EP = 2
(d) m<OFH = 178/2 = 89; inscribed angle is half measure of intercepted arc
The problem given can be solve using one variable. so let x be the total vote
x = x(5/8) + 5/9(x - x(5/8)) + 48
so solve for x
x - x(5/8) - 5/9(x - x(5/8)) = 48
x - x(5/8) - x(5/9) + x(25/72) = 48
x(1/6) = 48
x = 48*6
x = 288
blue votes = 288(5/8) = 180
red votes = 5/9(288 - 180) = 60
students riverside = 288 + 25 = 313
A * b = 21 and b * c = 39. then b is the common factor of the two numbers.
We need to factor these two numbers to know their equivalent values.
21 factors are 1, 3, 7, 21
39 factors are 1, 3, 13, 39
if b = 3, then a = 7 and c = 13.
To check:
a * b = 21 where 7 * 3 = 21 and b * c = 39 where 3 * 13 = 39
We can then conclude the following:
3 is lesser than 7 which is lesser than 13. where b < a < c
OR 13 is greater than 7 which is greater than 3. where c > a > b
not sure if these answers are included in your choices but i hope this helps.
120+72+24+24+96=336 cm cubed
C