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irina1246 [14]
4 years ago
9

The electric usage for a computer repair company was charted over four months. What is the rate of change for the bill during th

at time? KWH used Billing 578 $109.82 1,033 $196.27 1,475 $280.25 1,754 $333.26 A. $0.56 per KWH B. $1.79 per KWH C. $0.19 per KWH
Mathematics
1 answer:
Lady_Fox [76]4 years ago
5 0

Answer:

The correct option is;

C. $0.19 per KWH

Step-by-step explanation:

The given data are;

KWH   {}               Billing

578   {}                 $109.82

1,033   {}               $196.27

1,475   {}               $280.25

1,754   {}               $333.26

Therefore, we have the rate of change, m, given as follows;

m =(Change in the amount paid)/(Change in the electric usage in the same period)

For the first and second month, the rate of change is therefore;

m = ($196.27 - $109.82)/(1,033 - 578) = $0.19 per kWH

Between the first and third month, the rate of change is given as follows;

m = ($280.25 - $109.82)/(1,475 - 578) = $0.19 per kWH

Between the first and fourth month, the rate of change is given as follows;

m = ($333.26 - $109.82)/(1,754 - 578) = $0.19 per kWH

Therefore;

The rate of change is constant and is $0.19 per kWH

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