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zmey [24]
3 years ago
5

Which of the inequalities represents the statement "the absolute value of the difference of x and y is greater than 5"?

Mathematics
1 answer:
anzhelika [568]3 years ago
5 0

Answer:

Step-by-step explanation:

The absolute value of the difference of x and y is represented by subtracting y from x and taking the absolute value of the entire expression; the correct answer is |x - y| > 5.

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Need help with this math please.
Cerrena [4.2K]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
A parllogram has a hight of 3.5 and the weith is 3.1 what is the area
scZoUnD [109]
Area of parallelogram = width x height
Area of parallelogram = 3.1 x 3.5
Area of parallelogram = 10.85 unit²
5 0
3 years ago
For the years from 2002 and projected to 2024, the national health care expenditures H, in billions of dollars, can be modeled b
dmitriy555 [2]

Answer:

2019.

Step-by-step explanation:

We have been given that for the years from 2002 and projected to 2024, the national health care expenditures H, in billions of dollars, can be modeled by H = 1,500e^{0.053t} where t is the number of years past 2000.

To find the year in which national health care expenditures expected to reach $4.0 trillion (that is, $4,000 billion), we will substitute H=4,000 in our given formula and solve for t as:

4,000= 1,500e^{0.053t}

\frac{4,000}{1,500}=\frac{ 1,500e^{0.053t}}{1,500}

\frac{8}{3}=e^{0.053t}

e^{0.053t}=\frac{8}{3}

Take natural log of both sides:

\text{ln}(e^{0.053t})=\text{ln}(\frac{8}{3})

0.053t\cdot \text{ln}(e)=\text{ln}(\frac{8}{3})

0.053t\cdot (1)=0.9808292530117262

\frac{0.053t}{0.053}=\frac{0.9808292530117262}{0.053}

t=18.506212320

So in the 18.5 years after 2000 the expenditure will reach 4 trillion.

2000+18.5=2018.5

Therefore, in year 2019 national health care expenditures are expected to reach $4.0 trillion.

7 0
3 years ago
Pls help I will mark brainliest quick
azamat

Answer:

the picture is blocked

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The cycle time for trucks hauling concrete to a highway construction site is uniformly distributed over the interval 40 to 75 mi
jeka57 [31]

Answer:

0.8333 = 83.33% probability that the cycle time exceeds 50 minutes if it is known that the cycle time exceeds 45 minutes

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

P(X > x) = \frac{b - x}{b - a}

Uniformly distributed over the interval 40 to 75 minutes.

This means that a = 40, b = 75

It is known that the cycle time exceeds 45 minutes

This means that we can use a = 45

What is the probability that the cycle time exceeds 50 minutes?

P(X > 50) = \frac{75 - 50}{75 - 45} = 0.8333

0.8333 = 83.33% probability that the cycle time exceeds 50 minutes if it is known that the cycle time exceeds 45 minutes

8 0
3 years ago
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