Answer:
The required vectors are 
and 
.
Step-by-step explanation:
Given information: P(-4,-2) and Q(3,-4).
We need to find the two vectors parallel to 
with length 2.
If 
and 
, then
Using the above formula we get
vector QP is,
Magnitude of vertor QP is,
Using vector is
Multiply vector w by 2 to get a parallel vector parallel of QP in same direction.
Multiply vector w by -2 to get a parallel vector parallel of QP in opposite direction.
Therefore the required vectors are and .
Answer:
Let's solve for f.
4
r
+
8
f
=
5
g
Step 1: Multiply both sides by fr.
4f+8r=
5fr
g
Step 2: Multiply both sides by g.
4fg+8gr=5fr
Step 3: Add -5fr to both sides.
4fg+8gr+−5fr=5fr+−5fr
4fg−5fr+8gr=0
Step 4: Add -8gr to both sides.
4fg−5fr+8gr+−8gr=0+−8gr
4fg−5fr=−8gr
Step 5: Factor out variable f.
f(4g−5r)=−8gr
Step 6: Divide both sides by 4g-5r.
f(4g−5r)
4g−5r
=
−8gr
4g−5r
f=
−8gr
4g−5r
Answer:
f=−8gr4g−5r
Answer:
1/3
Step-by-step explanation:
2nd one
Answer: Choice B)
Explanation:
You mentioned there isn't a diagram to go with this, but I'm assuming that this problem is referring to a previous problem you posted. In that problem, it mentions that point W is at (1,-2). If we apply the scale factor 3, then we're tripling each coordinate. That means x = 1 becomes x = 3, and y = -2 becomes y = -6
We can write it like this:
(1,-2) ---> 3*(1, -2) = (3*1, 3*(-2) ) = (3, -6)
Only choice B has W'(3,-6) so this is likely the final answer.
If we apply this dilation to every point, then that effectively makes quadrilateral W'X'Y'Z' to be three times longer and taller than compared to quadrilateral WXYZ. In other words, its side lengths are 3 times longer.
