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Morgarella [4.7K]
4 years ago
14

At the grocery store watermelon costs $1.27 per pound. If Heather buys a 5.5 lb watermelon, which proportion could she use to fi

nd out how much it will cost, c?
Mathematics
2 answers:
Helga [31]4 years ago
7 0
If you would like to know how much will the watermelon cost, you can calculate this using the following steps:

$1.27 ... 1 pound
$c = ? ... 5.5 pounds

1.27 * 5.5 = 1 * c
c = 1.27 * 5.5
c = $6.99

The correct result would be: <span>c = $1.27 * 5.5 pounds = $6.99.</span>
STALIN [3.7K]4 years ago
3 0

Answer:

It's D.) 1/1.27 = 5.5/c

Step-by-step explanation:

Set up the proportion to be  

weight in pounds

cost

. Keeping the variables the same on both sides the correct proportion is

1 /1.27

=  

5.5 /c .

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-3(2x-3)+10x=39 what’s the answer
Temka [501]
Decimal form= 7.5 , fraction form = 15/2 , improper fraction= 7 and 1/2
3 0
3 years ago
Which value for x makes the open sentence true? 5⋅x+1=1+x2 5 4 3 2
Aleksandr-060686 [28]

Hey!

Let's solve this together.

5x+1 = 1+x2

Possible Answers: {5,4,3,2}

Lets start with 5.

5(5)+1 = 1+2(5)***

25+1 = 1+10

26 ≠ 11

So, 5 is NOT the answer.

Now, 4.

5(4)+1 = 1+(4)2

20+1 = 1+8

21 ≠ 9

So, 4 is NOT the answer.

Now, 3.

5(3)+1 = 1+(3)2

15+1 = 1+6

16 ≠ 7

So, 3 is NOT the answer.

Lastly, 2.

5(2)+1 = 1+(2)2

10+1 = 1+4

11 ≠ 5

So, 2 is NOT an answer.

So, the answer is: None of the above. None of them can be answers because none of them make the statement true.

***(In algebra, we start using parenthesis instead of the dot for multiplication when using numbers.)

Hope this helps!

<h2><em>~~PicklePoppers~~</em></h2>
3 0
3 years ago
The radius of a sphere is increasing at a rate of 4 mm/s. How fast is the volume increasing (in mm^3/s) when the diameter is 60
nexus9112 [7]

Answer:

The volume is increasing at a rate of 1508 cubic millimeters per second when the diameter is 60 mm.

Step-by-step explanation:

Volume of a sphere:

The volume of a sphere is given by the following equation:

V = \frac{4\pi r^3}{3}

In which r is the radius.

Implicit derivatives:

This question is solving by implicit derivatives. We derivate V and r, implicitly as function of t. So

\frac{dV}{dt} = 4\pi r^2 \frac{dr}{dt}

The radius of a sphere is increasing at a rate of 4 mm/s.

This means that \frac{dr}{dt} = 4

How fast is the volume increasing (in mm^3/s) when the diameter is 60 mm?

This is \frac{dV}{dt} when r = \frac{d}{2} = \frac{60}{2} = 30. So

\frac{dV}{dt} = 4\pi r^2 \frac{dr}{dt}

\frac{dV}{dt} = 4\pi*(30)^2*4

\frac{dV}{dt} = 1508

The volume is increasing at a rate of 1508 cubic millimeters per second when the diameter is 60 mm.

7 0
3 years ago
In one college, 67 students made the dean's list. If this was 33.5% of the student body, what was the total number of students i
poizon [28]

Answer:

Total number of students in the college = 200 student

Step-by-step explanation:

Given:

Number of student make dean's list = 67 student

Percentage of student make dean's list = 33.5% of all student

Find:

Total number of students in the college

Computation:

Total number of students in the college = Number of student make dean's list / Percentage of student make dean's list

Total number of students in the college = 67 / 33.5%

Total number of students in the college = 67 / 0.335

Total number of students in the college = 200 student

3 0
3 years ago
The map shows the route for a race.You are at X, 6000 ft from the first checkpoint C.The second checkpoint D is located at the m
Alex

Answer:

Distance between the two check point (C and D) is 4920 ft.

Step-by-step explanation:

From the question given above, we obtained the following information:

X is 6000 ft from C (1st check point)

D (2nd check point) is the midpoint point between C and Y ( the end of the race)

Total race = 3 miles

1 mile = 5280 ft

Next, we shall express the total race in feet (ft).

This is illustrated below:

1 mile = 5280 ft

Therefore,

3 miles = 3 × 5280 = 15840 ft

Next, we shall determine the distance between the 1st check point (C) and the end of the race (Y)

This can be obtained as follow:

Total distance = 15840 ft

Distance between X and C = 6000 ft

Distance between C and Y =?

Distance between C and Y = (Total distance) – (Distance between X and C)

Distance between C and Y = 15840 – 6000

Distance between C and Y = 9840 ft

Finally, we shall determine the distance between the two check point (C and D) as follow:

Since D is midpoint between C and Y, therefore, we shall we shall divide the distance between C and Y by 2 in order to obtain the distance between the two check point (C and D).

This is illustrated below:

Distance between C and Y = 9840 ft

Distance between the two check point (C and D) = 9840/2 = 4920 ft

Therefore, the distance between the two check point (C and D) is 4920 ft

5 0
3 years ago
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