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Elena L [17]
3 years ago
15

Solve 3m+7/2=−2m+5/2 what is m

Mathematics
2 answers:
GenaCL600 [577]3 years ago
5 0
Solve for m:3 m + 7/2 = 5/2 - 2 m
Put each term in 3 m + 7/2 over the common denominator 2: 3 m + 7/2 = (6 m)/2 + 7/2:(6 m)/2 + 7/2 = 5/2 - 2 m
(6 m)/2 + 7/2 = (6 m + 7)/2:(6 m + 7)/2 = 5/2 - 2 m
Put each term in 5/2 - 2 m over the common denominator 2: 5/2 - 2 m = 5/2 - (4 m)/2:(6 m + 7)/2 = 5/2 - (4 m)/2
5/2 - (4 m)/2 = (5 - 4 m)/2:(6 m + 7)/2 = (5 - 4 m)/2
Multiply both sides by 2:6 m + 7 = 5 - 4 m
Add 4 m to both sides:6 m + 4 m + 7 = (4 m - 4 m) + 5
4 m - 4 m = 0:6 m + 4 m + 7 = 5
6 m + 4 m = 10 m:10 m + 7 = 5
Subtract 7 from both sides:10 m + (7 - 7) = 5 - 7
7 - 7 = 0:10 m = 5 - 7
5 - 7 = -2:10 m = -2
Divide both sides of 10 m = -2 by 10:(10 m)/10 = (-2)/10
10/10 = 1:m = (-2)/10
The gcd of -2 and 10 is 2, so (-2)/10 = (2 (-1))/(2×5) = 2/2×(-1)/5 = (-1)/5:Answer: m = (-1)/5
Dovator [93]3 years ago
4 0

Answer:

-2/5

Step-by-step explanation:

3m + 7/2 = -2m + 5/2

3m + 7 = -2m + 5

5m = -2

m = -2/5

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Step-by-step explanation:

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Write the rule for finding a point translated vertically k units up. 2. Use this rule to find the coordinates for (−3, −6) when
Alex17521 [72]

Answer:

Rule is (x, y+k)

New point is (-3,9)

Step-by-step explanation:

A point translated vertically k units up means the x coordinate remains the same in the translation but the y coordinate is increased by k units

This can be represented mathematically as;

Let;s assume the point to be A with coordinates (x,y) then to get the image of the point under  a vertical translation k units up you add k to the y coordinate value.

Given ;

A=(\frac{x}{y} )\\\\T=(0,k)\\\\A'=(\frac{x}{y} )+(\frac{0}{k} )=(\frac{0+x}{y+k} )\\\\A'=\frac{x}{y+k} =(x,y+k)

where T is the translation

In the question

Given (-3,-6) and T is (0,5) the new coordinate will be

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Answer:

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Step-by-step explanation:

The expression:

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(x-2)² + 30 = 10y

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General vertex form is:

y = a(x-h)² + k

then, the vertex is locate at (h, k). In this case the vertes is (2, 3), and <em>a </em>= 1/10

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