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Elena L [17]
3 years ago
15

Solve 3m+7/2=−2m+5/2 what is m

Mathematics
2 answers:
GenaCL600 [577]3 years ago
5 0
Solve for m:3 m + 7/2 = 5/2 - 2 m
Put each term in 3 m + 7/2 over the common denominator 2: 3 m + 7/2 = (6 m)/2 + 7/2:(6 m)/2 + 7/2 = 5/2 - 2 m
(6 m)/2 + 7/2 = (6 m + 7)/2:(6 m + 7)/2 = 5/2 - 2 m
Put each term in 5/2 - 2 m over the common denominator 2: 5/2 - 2 m = 5/2 - (4 m)/2:(6 m + 7)/2 = 5/2 - (4 m)/2
5/2 - (4 m)/2 = (5 - 4 m)/2:(6 m + 7)/2 = (5 - 4 m)/2
Multiply both sides by 2:6 m + 7 = 5 - 4 m
Add 4 m to both sides:6 m + 4 m + 7 = (4 m - 4 m) + 5
4 m - 4 m = 0:6 m + 4 m + 7 = 5
6 m + 4 m = 10 m:10 m + 7 = 5
Subtract 7 from both sides:10 m + (7 - 7) = 5 - 7
7 - 7 = 0:10 m = 5 - 7
5 - 7 = -2:10 m = -2
Divide both sides of 10 m = -2 by 10:(10 m)/10 = (-2)/10
10/10 = 1:m = (-2)/10
The gcd of -2 and 10 is 2, so (-2)/10 = (2 (-1))/(2×5) = 2/2×(-1)/5 = (-1)/5:Answer: m = (-1)/5
Dovator [93]3 years ago
4 0

Answer:

-2/5

Step-by-step explanation:

3m + 7/2 = -2m + 5/2

3m + 7 = -2m + 5

5m = -2

m = -2/5

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\huge{\boxed{\tt{Solution:-}}}

<h3><u>Given :</u></h3>
  • \sf {4x-6=10x-3}
<h3><u>T</u><u>o</u><u> </u><u>Find</u><u> </u><u>:</u></h3>
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\sf{(a.)\:x=\dfrac {-1}{2}}

\sf{(b.)\:x=-2}

\sf{(c.)\:x=\dfrac {1}{2}}

\sf{(d.)\:x=2}

Now, we solving it :

\sf{: \implies  {4x - 6 = 10x - 3}} \\  \\ \sf{: \implies  { - 6 + 3= 10x - 4x}} \\  \\ \sf{: \implies  { - 3= 6x}} \\  \\ \sf{: \implies  {  \dfrac{- 3}{6} = x}} \\  \\ \sf{: \implies  {\dfrac{- 1}{2} = x}} \\  \\  : \implies  {\boxed{ \sf{x =\dfrac{- 1}{2}}}}

\bf{\therefore{Correct \:solution\:is\:(a.)\:x=\dfrac {-1}{2}.}}

\rule {307}{2}

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