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4 years ago

The time is a quarter to 7 in the eveing write this is in 24 clock time

Mathematics

1 answer:

rewona [7]4 years ago

8 0

This would be 6:45 PM, or 18:45 in 24 hour time.

Hope this helps :)

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On a skiing trip there are five people but only three pairs of skis how many different groups of three could ski

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10 different groups can ski.

This is a combination of 5 items taken 3 at a time:
$_5C_3=\frac{5!}{3!(5-3)!}=\frac{5!}{3!2!}=\frac{120}{12}=10$

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3 years ago

As x → − ∞ , f ( x ) = − 3 . As x → ∞ , f ( x ) = − 3

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Answer:

Step-by-step explanation:

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2 years ago

60 is 1/100 of what?

Thepotemich [5.8K]

Answer:

60% or 0.6 as a decimal

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3 years ago

Rosie bought a car for £4000.

vovangra [49]

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3.5%

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3 years ago

The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$

c.The probability that all 12 can transact business in a foreign language= $12C_{12}(0.8)^0(0.2)^{12}$

The probability that all 12 can transact business in a foreign language= $\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}$

5 0

3 years ago