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3 years ago

11

Jose Rodriguez recently sold 1,320 shares of oil stock for $31.70 per share plus a commission of $29.95 plus $0.03 per share. He

paid a total of $56,166.00 for the stock. What is the amount of sale? What was the selling commission? What was the net sale? Was it a profit or loss?

1 answer:

Aleonysh [2.5K]3 years ago

5 0

Answer:

69

Step-by-step explanation:

420

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Police estimate that 25% of drivers drive without their seat belts. If they stop 6 drivers at random, find the probability tha

Furkat [3]

Answer:

17.80% probability that all of them are wearing their seat belts.

Step-by-step explanation:

For each driver stopped, there are only two possible outcomes. Either they are wearing their seatbelts, or they are not. The drivers are chosen at random, which mean that the probability of a driver wearing their seatbelts is independent from other drivers. So we use the normal probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Police estimate that 25% of drivers drive without their seat belts.

This means that 75% wear their seatbelts, so $p = 0.75$

If they stop 6 drivers at random, find the probability that all of them are wearing their seat belts.

This is $P(X = 6)$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.1780$

17.80% probability that all of them are wearing their seat belts.

3 0

3 years ago

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Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species

kotegsom [21]

Answer:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

Step-by-step explanation:

The logistic equation is the following one:

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that $P(0) = 80, K = 2000$ .

The number of fish tripled in the first year. This means that $P(1) = 3P(0) = 3(80) = 240$ .

Using the equation for P(1), that is, P(t) when $t = 1$ , we find the value of r.

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

$240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}$

$280*(2000 + 80(e^{r} - 1)) = 160000e^{r}$

$280*(2000 + 80e^{r} - 80) = 160000e^{r}$

$280*(1920 + 80e^{r}) = 160000e^{r}$

$537600 + 22400e^{r} = 160000e^{r}$

$137600e^{r} = 537600$

$e^{r} = \frac{537600}{137600}$

$e^{r} = 3.91$

Applying ln to both sides.

$\ln{e^{r}} = \ln{3.91}$

$r = 1.36$

This means that the expression for the size of the population after t years is:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

4 0

3 years ago

here are the first three terms of a different sequence 1 2 4 write down two numbers that cold be the 4th and 5th terms of this s

iris [78.8K]

Answer:

8, 16, ×2

Step-by-step explanation:

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2 years ago

Help plsssssssssssss

otez555 [7]

$c = 3p + 7$
I think this is the answer good luck

6 0

3 years ago

Gabrielle is 12 years younger than Mikhail. The sum of their ages is 76 . What is Mikhail's age?

Over [174]

Answer:

48 years old

Step-by-step explanation:

Let x = Mikhail's age

then x-15 = Gabrielle's age

x + x-15 = 81

2x-15 = 81

2x = 96

x = 48 years old

6 0

3 years ago

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