Summation of 3n + 2 from n = 1 to n = 14 = (3(1) + 2) + (3(2) + 2) + (3(3) + 2) + . . . + (3(14) + 2) = 5 + 8 + 11 + ... + 44 ia an arithmetic progression with first term (a) = 5, common difference (d) = 3 and last term (l) = 44 and n = 14
Sn = n/2(a + l) = 14/2(5 + 44) = 7(49) = 343
Therefore, the required summation is 343.
Answer:
80
Step-by-step explanation:
Parallel lines have the same slope. The equation of the parallel line is therefore:
y = x + b
Plug in the values you are given to find b:
2 = -3 + b
b = 5
There will be a 25 grams left after 3240 years.
The half-life of Radium-226 is 1620 years. If we divide 3240 by 1620 the answer is 2. So that means the amount of Radium-226 will divide in half twice.
100 / 2 = 50 / 2 = 25
Answer: the product is = 33+4i
Step-by-step explanation:
21+4i-12i^2
21+4i-12(-1) i^2=-1
21+4i+12
your answer would be 33+4i .
