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2 years ago

How can you use a right angle to dicide how to name another angle?

1 answer:

5 0

If it is a square, subtract (90+ whatever the other angle is) from 360. If it is a triangle than add 90 plus whatever other number the other angle is then subtract it from 180. A triangle is 180 degrees, and a square is 360 degrees.

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Can Someone PLEASE HELP WITH THIS IXL? PLEASE HELP!! I DONT GET IT. PLEASEE HELP!! THIS IS A 6th GRADE IXL!! PLEASEEE HELP

Alexxx [7]

< is the correct symbol

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2 years ago

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svlad2 [7]

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Step-by-step explanation:

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2 years ago

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Marizza181 [45]

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3 years ago

Find the gradient of the curve y=(2x-3)^5 at the point (2,1)

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<h3><em>Hope I helped you!</em></h3><h3><em>Success!</em></h3>

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3 years ago

Read 2 more answers

I need help from uh all..

DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

$\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})$

To prove this identity we will take the right side of the identity,

$\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})$

$=\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})$

$=\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]$

$=\frac{1}{2}(\frac{2}{\text{tan}A} )$ [Since $\text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}$ ]

= cot A

Hence right side of the equation is equal to the left side of the equation.

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3 years ago