Answer:
FfPp
Explanation:
If we take the two traits to be separate alleles, we can make flowers F (F is dominant; f is recessive) and pollen as P (P is dominant; p is recessive). So a pea plant with white flowers (recessive) and long pollen (dominant) will have the genotype ffPp or ffPP (because one dominant allele will express a dominant phenotype).
For this question, we will assume that the wild type (red flowers and long pollen) is homozygous, meaning it contains two dominant alleles.
If the wild type (FFPP) is crossed with the plant with white flowers and short pollen (ffpp), we can make a table illustrating the crosses. However, because there is only one possible gamete that each parent can form (FP and fp), we can assume that the F1 progeny will have identical genotypes, which can be expressed as FfPp (because combining the gamete from the wild type and the other parent can only give one phenotype).
I think that the answer is c because they are both named pinus
Answer:
Explanation:
The pellets from a barn owl often contain the remains of 4 or 5 small animals. Let's assume an average of 4.5 animals per day.
1. Animals per week
2. Animals per year
3. Animals per month
The normal osmolality of intracellular and extracellular fluid is 300 mosm, which makes them in osmotic<span> equilibrium. </span>
<span>This condition is better described as isosmotic. Water moves from high salt concentration to low salt concentration due to osmosis. The osmotic pressure of the extracellular fluid equals the osmotic pressure of the intracellular fluid (300 mosm), therefore no fluid movement across the plasma membrane.</span>
