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wlad13 [49]
3 years ago
13

Carpet is sold in square yards. How much carpet would a person need to buy for a rectangular room that has dimensions of 10 yard

s by 18 feet?
Mathematics
1 answer:
german3 years ago
3 0
60 square yards is the answer.
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HELP PLEASE AFTER THIS ILL BE DONE AND I CAN TURN IN M WORK
arsen [322]

Answer:

A, C, E for the first one; B, C, E for the second one; B and E for the last one

Step-by-step explanation:

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The area of a regular octagon is 35 cm 2 what is the area of a regular octagon with sides three times as large
Maurinko [17]
The area of a polygon = n*side^2 / (4 * tan(180/n))
where "n" is the number of sides

Let's calculate area for side = 2
area = 8*2^2 / (4 * tan(180/8))
area = 32 / (4 * tan(22.5))
area = 32 / 4*0.41421
<span> <span> <span> area = 19.3138746047 </span> </span> </span>

Now, let's calculate area for side = 6
area = 8*6^2 / (4 * tan(180/8))
area = 288 / <span> <span> <span> 1.65684 </span> </span> </span>
area = <span> <span> <span> 173.824871442 </span> </span> </span>

<span> <span> 173.824871442 </span> / </span><span><span>19.3138746047 = </span> 9

So, the area would be 9 times larger.

ALSO, looking at the formula
</span>n*side^2 / (4 * tan(180/n))
we can see that the side length appears just once in the formula and we are to square it in the calculation.  So, if we increase the side length is increased by 3, then the area increases by 3^2 or 9.


5 0
3 years ago
Sam Long anticipates he will need approximately $227,300 in 14 years to cover his 3-year-old daughter's college bills for a 4-ye
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Answer:

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Step-by-step explanation:

4 0
3 years ago
Evaluate P(5, 2)<br><br> 20<br> 60<br> 240<br> 10
vesna_86 [32]

P(5,2) =  n! /(n-r)!

n = 5, r = 2:

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3 0
3 years ago
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How many area codes (abc) would be possible if all three digits could be any vaiue 1-9
kifflom [539]

Answer:

<u>The total number of area codes that would be possible if all three digits could be any value from 1 to 9 is 729.</u>

Step-by-step explanation:

1. Let's start our reasoning to get this answer:

From 000 to 999, we have 1,000 possible area codes.

But for this question, we should find out the answer without considering the digit 0, therefore we must exclude:

A. From 000 to 099, that are 100 possible area codes.

B. We also have to exclude, from 100 to 110, 120, 130, 140, 150, 160, 170, 180 and 190. Those are 19 area codes more.

C. We also have to exclude these same options of code areas, for 200 - 210 and 2x0, and 19 more for each subset that starts with 3, 4, 5, 6, 7, 8 and 9. In total, 19 multiplied by 8, 152 numbers more.

<u>Therefore, the total number of area codes that would be possible if all three digits could be any value from 1 to 9 is:</u>

<u>1,000 - 100 - 19 - 152 = 729</u>

<u>The simplest way to find it, is:</u>

<u>For 000 to 999 = 1,000 or 10³</u>

<u>Excluding the digit zero = 729 or 9³</u>

3 0
3 years ago
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