Answer:
s = √(3V/[8 in])
Step-by-step explanation:
Where are "the following functions" that were mentioned in this problem statement? Please share them. Thanks.
The volume of a right square pyramid is V = (1/3)(area of base)(height). In more depth, V = (1/3)(s²)(h). We want to solve this for s.
Multiplying both sides by 3 to eliminate the fractional coefficient, we get:
3V = s²(h), and so s² = 3V/h.
Taking the square root of this, we get:
s = √(3V/h).
Now let's substitute the given numerical value for the height:
s = √(3V/[8 in]). We could also label this as a(V) as is done in the problem statement.
![\csc\text{B}\in(-\infty,-1]\cup[1,\infty)](https://tex.z-dn.net/?f=%5Ccsc%5Ctext%7BB%7D%5Cin%28-%5Cinfty%2C-1%5D%5Ccup%5B1%2C%5Cinfty%29)