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zmey [24]
3 years ago
8

Need help setting this up? Please help me!

Mathematics
1 answer:
Dvinal [7]3 years ago
6 0

Answer:$1500was invested in the account that gained 15% and $15500 was invested in the account that lost 5%.

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Which is the decimal expansion of the following 1/5
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Decimal expansion of 1/5 = 0.2

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The average number of employees that call in sick for the day over the course of a year is 25.
sveta [45]

Answer:

<h3>x¯= 23.8 </h3><h3>μ= 8.2 </h3>

Step-by-step explanation:

<h3>Find the mean. </h3>

 

The mean of a set of numbers is the sum divided by the number of terms.

x¯= <u>25+10+16+39+27+25+32+25+25+22+28+14</u>

                                   11

<h3>Simplify the numerator. </h3>

x¯ = <u>261.27</u>

            11

<h3>Divide  261.27 by 11 </h3>

x¯= 23.75 18

<h3>Divide. </h3>

x¯= 23.75 18

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

x¯=23.8

<h3>Simplify each value in the list. </h3>

25,10,16,39.27,25,32,25,25,22,28,14

Set up the formula for sample standard deviation. The standard deviation of a set of values is a measure of the spread of its values.

s=  n^∑  i=1    √(<u>xi−xavg</u>)²

                            N-1

             

Set up the formula for standard deviation for this set of numbers.

s= ⎷(25−23.8)²+(10−23.8)²+(16−23.8)²+(39.27−23.8)²+(25−23.8)²+<u>(32−23.8)²+(25−23.8)²+(25−23.8)²+(22−23.8)²+(28−23.8)²+(14−23.8)</u>²

                                       11−1

<h3>Simplify the result. </h3>

 

s= √68.05209

The standard deviation should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

8.2

7 0
3 years ago
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