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4 years ago

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Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t

hree options.

1 answer:

borishaifa [10]4 years ago

8 0

Answer:

<em>Next time, please upload your option.</em>

The line 5x − 2y = −6 <=> 2y = 5x + 6 <=> y = (5/2)x + 3, has the slope a = 5/2

=> Another line (y = a'x + b) that is perpendicular with this line, must has slope a', that satisfies: a' x (5/2) = -1 => a' = -2/5

=> y = (-2/5)x + b

This line passes (5, -4), then we have:

-4 = (-2/5)*5 + b => -4 = -2 + b => b = -2

=> Solution is y = (-2/5)x -2

Hope this helps!

:)

You might be interested in

Regular hexagon ABCDEF is inscribed in circle X and has an apothem that is 6√3 inches long. Use the length of the apothem to cal

Phantasy [73]

Answer:

Part A

$The \ circumradius, \ R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}$

Plugging in the given values we get;

$The \ circumradius, \ R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3} \times \dfrac{2}{\sqrt{3} } = 12$

R = 12 inches

The radius of the circumscribing circle is 12 inches

Part B

The length of each side of the hexagon, 's', is;

$s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)$

Therefore;

$s = 6 \cdot \sqrt{3} \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3} \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12$

s = 12 inches

The perimeter, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon is 72 inches

Step-by-step explanation:

The given parameters of the regular hexagon are;

The length of the apothem of the regular hexagon, a = 6·√3 inches

The relationship between the apothem, 'a', and the circumradius, 'R', is given as follows;

$a = R \cdot cos \left(\dfrac{\pi}{n} \right)$

Where;

n = The number of sides of the regular polygon = 6 for a hexagon

'a = 6·√3 inches', and 'R' are the apothem and the circumradius respectively;

Part A

Therefore, we have;

$The \ circumradius, \ R = \dfrac{a}{cos \left(\dfrac{\pi}{n} \right)}$

Plugging in the values gives;

$The \ circumradius, \ R = \dfrac{6 \cdot \sqrt{3} }{cos \left(\dfrac{\pi}{6} \right)} = \dfrac{6 \cdot \sqrt{3} }{\left(\dfrac{\sqrt{3} }{2} \right)} = 6 \cdot \sqrt{3} \times \dfrac{2}{\sqrt{3} } = 12$

The circumradius, R = 12 inches

Part B

The length of each side of the hexagon, 's', is given as follows;

$s = a \times 2 \times tan \left(\dfrac{\pi}{n} \right)$

Therefore, we get;

$s = 6 \cdot \sqrt{3} \times 2 \times tan \left(\dfrac{\pi}{6} \right) = 6 \cdot \sqrt{3} \times 2 \times \left(\dfrac{1}{\sqrt{3} } \right) = 12$

The length of each side of the hexagon, s = 12 inches

The perimeter of the hexagon, P = n × s = 6 × 12 = 72 inches

The perimeter of the hexagon = 72 inches

5 0

3 years ago

Need math help (last one wouldn't let me upload pic)

Scrat [10]

Answer:

$\text{Area of the figure}=54\text{ unit}^2$

Step-by-step explanation:

Please find the attachment.

Let us divide our given image in several parts and then we will find area of different parts.

First of all let us find the area of our red rectangle with side lengths 6 units and 7 units.

$\text{Area of rectangle}=\text{Length*Width}$

$\text{Area of red rectangle part}=6\text{ units}\times 7\text{ units}$

$\text{Area of red rectangle part}=42\text{ units}^2$

Now let us find area of yellow triangle on the top of red rectangle. We can see that base of triangle is 6 units and height is 1 unit.

$\text{Area of triangle}=\frac{1}{2}\times \text{Base*Height}$

$\text{Area of triangle}=\frac{1}{2}\times \text{6 units *1 unit}$

$\text{Area of triangle}=3\text{ unit}^2$

Let us find the area of green triangle.

$\text{Area of green triangle}=\frac{1}{2}\times \text{3 units *2 units}$

$\text{Area of green triangle}=3\text{ unit}^2$

Now we will find the area of blue triangle, whose base is 6 units and height is 2 units.

$\text{Area of blue triangle}=\frac{1}{2}\times \text{6 units *2 units}$

$\text{Area of blue triangle}=6\text{ units}^2$

Let us add all these areas to find the area of our figure.

$\text{Area of the figure}=42\text{ units}^2+3\text{ unit}^2+3\text{ unit}^2+6\text{ unit}^2$

$\text{Area of the figure}=(42+3+3+6)\text{ unit}^2$

$\text{Area of the figure}=54\text{ unit}^2$

Therefore, area of our given figure is 54 square units.

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4 years ago

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fomenos

Answer:

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3 years ago

The lowest elevation in a region is at the bottom of a valley ?(negative 264 ?ft), and the highest elevation is at the top of a

gtnhenbr [62]

Answer:

The change in elevation is 20,744 ft

Step-by-step explanation:

Let

x -----> the lowest elevation in a region

y -----> the highest elevation in a region

we have that

x=-264 ft

y=+20,480 ft

We know that

To find out the change in elevation from the lowest elevation to the highest elevation, subtract the lowest elevation from the highest elevation (or find the difference in absolute value)

so

y-x

substitute the values

$20,480-(-264)$

$20,480+264=20,744\ ft$

4 0

4 years ago

Find the least common denominator 5,11

IceJOKER [234]

The correct answer to this question is 55.

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4 years ago

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