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Naya [18.7K]
3 years ago
14

Solve r/n + t = 4v for r

Mathematics
2 answers:
lana [24]3 years ago
8 0
Since r is being divided by N, we need to multiply both sides by N.
We are left with R + T = 4v/n
Now, we subtract T from each side. The equation is now R = 4V/N - T
We have now solved for R.
Furkat [3]3 years ago
5 0

r/n+t=4v

r/n+t-t=4v-t

r/n=4v-t

(n)r/n+4v-t(n)

r=4vn-tn

r=n(4v-t)

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The area of each book is 63 in2. The height of the stack is 15.75 inches. What is the volume of the stack of books?
Masteriza [31]
Do 63*15.75 and you should get your answer
992 1/2

4 0
3 years ago
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y=-2x-7.A new path will be built perpendicular to this path. The paths will intersect at the point(-2,-3). Identify the equation
Over [174]

Answer:

y=1/2 x -2 is the perpendicular line equation

Step-by-step explanation:

y=1/2 x + b

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5 0
3 years ago
If x varies directly as y, and y=6 when x=27, find x when y=2
shusha [124]

Answer:

x = 9

Step-by-step explanation:

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x = ky ← k is the constant of variation

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27 = 6k ( divide both sides by 6 )

4.5 = k

x = 4.5y ← equation of variation

When y = 2 , then

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6 0
3 years ago
v = 20.8x^2 - 458.3x + 3,500 represents the value of a car from 1964 to 2002. What year did the car have the least value? (x= 0
Karo-lina-s [1.5K]
See the picture for all detail, I have done it by hand.
Few important steps;
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-As, the 2nd derivative is positive so it is the least value

As x=0 in 1964 add 11 to it so at x=11 we get 1975 so in this year car have least value

7 0
4 years ago
A quadrilateral has vertices at A(–5, 5), B(1, 8), C(4, 2), D(–2, –2). Use slope to determine if the quadrilateral is a rectangl
lianna [129]

With the properties of rectangle in mind we must perform two verification. Verify to see if opposite sides are parallel and adjacent sides are perpendicular.

We need to determine the slope of each side, using the formula,

m=\frac{y_2-y_1}{x_2-x_1 }

<u>Slope  of AB</u>

m_{AB}=\frac{8-5}{1--5}

\Rightarrow m_{AB}=\frac{8-5}{1+5}

\Rightarrow m_{AB}=\frac{3}{6}

\Rightarrow m_{AB}=\frac{1}{2}


<u>Slope of BC</u>

m_{BC}=\frac{2-8}{4-1}

\Rightarrow m_{BC}=\frac{-6}{3}

\Rightarrow m_{BC}=-2

<u>Slope of CD</u>

m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-2-2}{-2-4}

\Rightarrow m_{CD}=\frac{-4}{-6}

\Rightarrow m_{CD}=\frac{2}{3}

<u>Slope of AD</u>

m_{AD}=\frac{-2-5}{-2--5}

\Rightarrow m_{AD}=\frac{-2-5}{-2+5}

\Rightarrow m_{AD}=\frac{-7}{3}

<u>Verify Parallel sides</u>

If the quadrilateral is a rectangle, then opposite sides should have the same slope. But

m_{AD} = \frac{-7}{3} \neq m_{BC}=-2

m_{AB}=\frac{1}{2} \neq m_{CD}=\frac{2}{3}


<u>Verify Perpendicularity</u>

And also the product of slopes of all sides with a common vertex should be -1. But

m_{AB} \times m_{BC}=\frac{1}{2} \times -2=-1

m_{AB} \times m_{AD}=\frac{1}{2} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{AD}=\frac{2}{3} \times -\frac{7}{3} \neq -1


\Rightarrow m_{CD} \times m_{BC}=\frac{2}{3} \times -2 \neq -1


Since the quadrilateral fails to satisfy all these conditions, the quadrilateral is not a rectangle




6 0
3 years ago
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