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marta [7]
3 years ago
5

The cost (c) in dollars to rent a chain saw for h hours is found using the equation c = 3h + 6 How much would it cost to rent th

e saw for 12 hours?
Mathematics
1 answer:
3241004551 [841]3 years ago
4 0

Answer:

42

Step-by-step explanation:

c= 3*12 + 6

c=36+6

c=42

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Determine whether the following function is one-to-one. f ( x ) = 6 x + 1
seraphim [82]

Answer:

one to one function

Step-by-step explanation:

f(x)=6x+1 can only be a one to one function when x1=x2

Now,

f(x1)=f(x2)

or, 6x1 + 1 = 6x2 + 1

or, 6x1 = 6x2

or, x1 = x2

So f(x)= 6x + 1 is a one to one function

4 0
2 years ago
I will mark you the brainiest for the correct answer, please be correct, Have a good day and take care, thanks. ( VIEW THE IMAGE
makkiz [27]

Mistake in Line 2 : Was in the determining the values for a ,b,c

Mistake in Line 4 : Not taking the square roots of both sides.

Step-by-step explanation:

{a}^{2}  +  {b}^{2}  =  {c}^{2}

First Mistake : Line 2

a = x \\ b = 6 \\ c = 10

Second Mistake : Line 4

136 =  {x}^{2}  \\ not \\ 136 = x

Correct Solution :

{x}^{2}  +  {6}^{2}  =  {10}^{2}  \\  {x}^{2}  =  {10}^{2}  -  {6}^{2}  \\  {x}^{2}  = 100 - 36 \\

{x}^{2}  = 64 \\  \sqrt{ {x}^{2} }  =  \sqrt{64}  \\ x = 6

3 0
3 years ago
The slope of the line that passes through the points (6, w) and (10, 4) is 8. What is the value of w?
RoseWind [281]

Answer:

My student the slope paserea the Pointe 6w and 10,4 is8

3 0
3 years ago
Read 2 more answers
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
The temperature one afternoon at 3 PM
prohojiy [21]

Answer:

Your answer is 49 degrees

Step-by-step explanation:

66 - 17 = 49

7 0
3 years ago
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