A=-32 (acceleration is the constant g) integrating with respect to t
v=-32t+vi but initial velocity is equal to zero as it is just "dropped".
h=-32t^2/2+hi, since the initial height is 144 ft
h(t)=-16t^2+144
The object will be at the ground when h(t)=0
-16t^2+144
-16(t^2-9)=0
-16(t+3)(t-3)=0, but since we know t>0
t=3 seconds.
Answer:
y = 1.3
Step-by-step explanation:
18y - 17 = 7
18y = 7 + 17
18y = 24
y = 24/18
y = 1.3
hope it helps!
Answer:
obhjuvhvvg
Step-by-step explanation:
Answer: Turbo jet pack: 6d + 7; x-ray vision glasses: 2d-5; Invisible shield: 10d + 1
Step-by-step explanation:
There’s not really any math needed because it’s put into words.
