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3 years ago

This data set represents the number of cups of coffee sold in a café between 8 a.m. and 10 a.m. every day for 14 days.

2 answers:

8 0

<span>4 days gives us 14 numbers to play with a quartile is 1/4 of the data set (by count). so 1q = 14/4 sort the numbers from small to large and find the 1q and 3q values</span>

algol133 years ago

7 0

The interquartile range (IQR) is the difference between quartile 3 and quartile 1. In this data set the IQR = 6

4,5,6,6,7,8,9,9,10,10,12,12,14,15

Q1 = 6
Q2 = 9
Q3 = 12

IQR = Q3 - Q1 = 12 - 6 = 6

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Graph the image of the given triangle under a dilation with a scale factor of -3 and center of dilation (0,0).

Svetlanka [38]

The points would be (9,9) , (0,-6) , (6,-9)
I hope this helps !

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3 years ago

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In the formula that gives the circumference of a circle, which quantity is

Vinil7 [7]

a (radius)

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3 years ago

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Point Q' is the image of Q(-4, 7) under a translation by 4 units to the right and 2 units down.

Reil [10]

Answer:

Q' ( 0,5)

Step-by-step explanation:

Q(-4, 7)

To shift to the right, add the amount to x

x+4

To shift down, subtract from y

y -2

Q' ( -4+4, 7-2)

Q' ( 0,5)

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2 years ago

What is StartFraction pi Over 3 EndFraction radians converted to degrees? If necessary, round your answer to the nearest degree.

Oliga [24]

Answer: 60°

Step-by-step explanation:

π/3

Since π is denoted as 180°, the question can be rewritten as:

π/3 .

To convert π/3 radians to the nearest degree will be:

π/3 = 180/3

= 60°

4 0

3 years ago

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A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w

DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 21.5, \sigma = 4.7$

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

$Z = \frac{X - \mu}{\sigma}$

$1.175 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.175*4.7$

$X = 27.0225$

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

$Z = \frac{X - \mu}{\sigma}$

$1.04 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.04*4.7$

$X = 26.388$

The lowest score that would meet the colleges requirement would be decreased to 26.388.

6 0

4 years ago