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Sladkaya [172]
3 years ago
6

What is 0.4 divided by 5.12 in long division

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0
Start by mult. both 0.4 and 5.12 by 100.  What is 40 divided by 512?

        ___.078_______________
512 /  40.000
           3584
          -----------
             4160
             4096
           ---------
                 64              and so on.   Calculator answer is 0.078125.
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Simplify and leave in radical form.<br><br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7Bx%5E%7B2%7D%20y%5E%7B6%7D%20%7D"
ikadub [295]

Answer: 0.0

Step-by-step explanation:

6 0
3 years ago
1/2 x (48 divided by 6) - 2 + 5
IceJOKER [234]

Answer:

7

Step-by-step explanation:

1/2<u>(48/6)</u> - 2 + 5

<u>1/2(8)</u> - 2 + 5

<u>4 - 2</u> + 5

<u>2 + 5</u>

7

6 0
3 years ago
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Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
IrinaK [193]

Answer:

1. The minimum head breadth that will fit the clientele is of 3.95-in.

2. The maximum head breadth that will fit the clientele is of 9.25-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 6.6-in and a standard deviation of 1.1-in.

This means that \mu = 6.6, \sigma = 1.1

1. What is the minimum head breadth that will fit the clientele?

The 0.8th percentile, which is X when Z has a p-value of 0.008, so X when Z = -2.41.

Z = \frac{X - \mu}{\sigma}

-2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = -2.41*1.1

X = 3.95

The minimum head breadth that will fit the clientele is of 3.95-in.

2. What is the maximum head breadth that will fit the clientele?

The 100 - 0.8 = 99.2nd percentile, which is X when Z has a p-value of 0.992, so X when Z = 2.41.

Z = \frac{X - \mu}{\sigma}

2.41 = \frac{X - 6.6}{1.1}

X - 6.6 = 2.41*1.1

X = 9.25

The maximum head breadth that will fit the clientele is of 9.25-in.

8 0
3 years ago
PLEASE HELP
Svetlanka [38]
The answer to this b
3 0
3 years ago
What is 11/25 as a percent
dem82 [27]
0.44 is your answer        
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