Well 12 x 5 = 60 so that one is correct for the GCF. The one for LCM i dont think you got that right. I dont know the answer for that but i do know that when it is wanting a Least Common Mulitple it means it wants the LEAST, lowest number.
<span>In this problem,think of it this way. 1 is to 22 as 1.6 is to X.
When you solve for X you will have the height of your school
all you need to do is multiply 1.6 by 22 and you've got it!
Cheers!</span>
Answer:
I think it is<u> D,</u> but I am not sure.
Step-by-step explanation:
Have a nice day!
Answer:
infinitely many solutions
Step-by-step explanation:
Given the simultaneous equation
4x=10+4y... 1
2x-2y=15 .... 2
_____________
4x-4y = 10 * 1
2x-2y = 15 * 2
__________--
4x-4y = 10
4x-4y = 30
Add both equation
8x - 8y = 10+30
8x-8y = 40
Divide though by 8
x-y = 5
x = 5 + y
Since the result gave 1 equation and 2 unknowns, then we will let x =k
k = 5 + y
y = k -5
k can be any integer
(x,y) = (k, k-5)
This show that the equation has infinitely many solutions
N÷3+1 or can be stated as 3÷n+1