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3 years ago

Which relation describes a function?

Mathematics

1 answer:

enot [183]3 years ago

4 0

Answer:

Step-by-step explanation:

A function is a relation that associates each element x of a set X to a single element y of another set Y.

{(0, 0); (0, 2); (2; 0); (2, 2)} NO FUNCTION

for 0 are two values, and for 2 are two values

{(-2, -3); (-3, -2); (2, 3); (3; 2)} FUNCTION

each number {-3, -2, 2, 3} has a single value

{(2, -1); (2, 1); (3, -1); (3, 1)} NO FUNCTION

for 2 are two values, and for 3 are two values

{(2, 2); (2, 3); (3, 2); (3, 3)} NO FUNCTION

for 2 are two values, and for 3 are two values

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3. If the Medicare tax rate is 5.4%, what

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The answer would be C. $40.85

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4 years ago

Read 2 more answers

1. In triangle ABC, m∠A=36, and m∠C=12. Calculate m∠B.

ki77a [65]

Answer:

1) m ∠B = 132°

2) m ∠B = 113°

Step-by-step explanation:

1. In triangle ABC, m ∠A=36, and m ∠C=12. Calculate m ∠B.

We are given measure of 2 angles and we need to find the third angle.

We know that, sum of angles of triangle = 180°

We can write as:

∠A + ∠B + ∠C = 180°

Now put m ∠A=36 and m ∠C=12, to find m ∠B

$\angle A + \angle B + \angle C = 180\\36+ \angle B +12=180\\\angle B+48=180\\\angle B=180-48\\\angle B=132$

So, we get m ∠B = 132°

2. In triangle ABC, m ∠A=40, and m ∠C=27. Calculate m ∠B.

We are given measure of 2 angles and we need to find the third angle.

We know that, sum of angles of triangle = 180°

We can write as:

∠A + ∠B + ∠C = 180°

Now put m ∠A=40 and m ∠C=27, to find m ∠B

$\angle A + \angle B + \angle C = 180\\40+ \angle B +27=180\\\angle B+67=180\\\angle B=180-67\\\angle B=113$

So, we get m ∠B = 113°

6 0

3 years ago

What is 9 - 2c + c = -13

Len [333]

9 - 2c + c = -13
9 - 3c = -13
-3c = -22
c = 7 1/3

6 0

4 years ago

Can someone help me please? <br><br> Thanks! <br><br> Please show your work and explain.

Liono4ka [1.6K]

1 Simplify 1/2x^2 to x^2/2
X^2/2 - x+5=0
2 Use the Quadratic Formula
x=1+3ı,1−3ı
So the answer is the first one a

6 0

3 years ago

Driving under the influence of alcohol (DUI) is a serious offense. The following data give the ages of a random sample of 50 dri

o-na [289]

Answer:

Explanation below.

Step-by-step explanation:

For this case we have the following dataset:

46, 16, 41, 26, 22 ,33, 30, 22 ,36, 34,

63, 21, 26, 18, 27, 24, 31, 38, 26, 55,

31, 47, 27, 43 ,35, 22 ,64,40, 58, 20,

49, 37, 53, 25, 29, 32, 23, 49, 39, 40,

24, 56, 30, 51, 21, 45, 27, 34, 47, 35

So we have 50 values. The first step on this case would be order the dataset on increasing way and we got:

16, 18, 20, 21, 21, 22, 22, 22, 23, 24,

24, 25, 26, 26, 26, 27, 27, 27, 29, 30

30, 31, 31, 32, 33, 34, 34, 35, 35, 36,

37, 38, 39, 40, 40, 41, 43, 45, 46, 47,

47, 49, 49, 51, 53, 55, 56, 58, 63, 64

We can find the range for this dataset like this:

$Range = Max-Min = 64-16 =48$

Then since we need 7 classes we can find the length for each class doing this:

$W = \frac{48}{7}=6.86$

And now we can define the classes like this and counting how many observations lies on each interval we got the frequency:

Class Frequency Midpoint RF CF

________________________________________________

[16-22.86) 8 19.43 (8/50)=0.16 0.16

[22.86-29.71) 11 26.29 (11/50)=0.22 0.38

[29.71-36.57) 11 33.14 (11/50)=0.22 0.6

[36.57-43.43) 7 40.0 (7/50)=0.14 0.74

[43.43-50.29) 6 46.86 (6/50)=0.12 0.86

[50.29-57.14) 4 53.72 (4/50)=0.08 0.94

[57.14-64] 3 60.57 (3/50)=0.06 1.0

________________________________________________

Total 50 1.00

RF= Relative frequency. CF= Cumulative frequency

The relative frequency was calculated as the individual frequency for a class divided by the total of observations (50)

The mid point is the average between the limits of the class.

And the cumulative frequency is calculated adding the relative frequencies for each class.

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4 years ago