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Goryan [66]
3 years ago
5

Which Statement is true? A.All Parallelograms are squares. B.All parallelograms are rhombuses. C.All rectangles are squares. D.A

ll squares are rhombuses.
Mathematics
2 answers:
Blababa [14]3 years ago
7 0
C is the correct option to choose
KonstantinChe [14]3 years ago
3 0
C is the correct answer


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What is the scale factor of figure B to figure A
maria [59]

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scale \:  \: factor =  \frac{25}{10}  =  \frac{10}{4}  =  \frac{21.5}{8.6} = 2.5  \\

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8 0
3 years ago
PLEASE ANSWER IN ONE MINUTE WILL MARK BRAINLIST
PSYCHO15rus [73]

Answer:

x=3

Step-by-step explanation:

3 0
2 years ago
On a coordinate plane, Point W is 5 units from the origin. If Point W is located at (3, y), which of these is a possible value f
Ray Of Light [21]

Answer:

W (3 , 4) or W (3 . -4)

Step-by-step explanation:

W (3 , y), origin (0 ,0)

WO = √(3-0)²+(y-0)² = √9+y²

WO = 5

√9+y² = 5

9+y² = 25

y² = 16

y = ± 4

W (3 , 4) or W (3 . -4)

6 0
3 years ago
Read 2 more answers
PLEASE HELP WITH GRADE 11 MATH. Make sure you show the formula. Substitute values and show all mathematicall operations! show yo
Degger [83]

3x+y

x

​

 

=−3

=−y+3

​

The second equation is solved for xxx, so we can substitute the expression -y+3−y+3minus, y, plus, 3 in for xxx in the first equation:

\begin{aligned} 3\blueD{x}+y &= -3\\\\ 3(\blueD{-y+3})+y&=-3\\\\ -3y+9+y&=-3\\\\ -2y&=-12\\\\ y&=6 \end{aligned}

3x+y

3(−y+3)+y

−3y+9+y

−2y

y

​

 

=−3

=−3

=−3

=−12

=6

​

Plugging this value back into one of our original equations, say x = -y +3x=−y+3x, equals, minus, y, plus, 3, we solve for the other variable:

\begin{aligned} x &= -\blueD{y} +3\\\\ x&=-(\blueD{6})+3\\\\ x&=-3 \end{aligned}

x

x

x

​

 

=−y+3

=−(6)+3

=−3

​

The solution to the system of equations is x=-3x=−3x, equals, minus, 3, y=6y=6y, equals, 6.

We can check our work by plugging these numbers back into the original equations. Let's try 3x+y = -33x+y=−33, x, plus, y, equals, minus, 3.

\begin{aligned} 3x+y &= -3\\\\ 3(-3)+6&\stackrel ?=-3\\\\ -9+6&\stackrel ?=-3\\\\ -3&=-3 \end{aligned}

3x+y

3(−3)+6

−9+6

−3

​

 

=−3

=

?

−3

=

?

−3

=−3

​

Yes, our solution checks out.

Example 2

We're asked to solve this system of equations:

\begin{aligned} 7x+10y &= 36\\\\ -2x+y&=9 \end{aligned}

7x+10y

−2x+y

​

 

=36

=9

​

In order to use the substitution method, we'll need to solve for either xxx or yyy in one of the equations. Let's solve for yyy in the second equation:

\begin{aligned} -2x+y&=9 \\\\ y&=2x+9 \end{aligned}

−2x+y

y

​

 

=9

=2x+9

​

Now we can substitute the expression 2x+92x+92, x, plus, 9 in for yyy in the first equation of our system:

\begin{aligned} 7x+10\blueD{y} &= 36\\\\ 7x+10\blueD{(2x+9)}&=36\\\\ 7x+20x+90&=36\\\\ 27x+90&=36\\\\ 3x+10&=4\\\\ 3x&=-6\\\\ x&=-2 \end{aligned}

7x+10y

7x+10(2x+9)

7x+20x+90

27x+90

3x+10

3x

x

​

 

=36

=36

=36

=36

=4

=−6

=−2

​

Plugging this value back into one of our original equations, say y=2x+9y=2x+9y, equals, 2, x, plus, 9, we solve for the other variable:

\begin{aligned} y&=2\blueD{x}+9\\\\ y&=2\blueD{(-2)}+9\\\\ y&=-4+9 \\\\ y&=5 \end{aligned}

y

y

y

y

​

 

=2x+9

=2(−2)+9

=−4+9

=5

​

The solution to the system of equations is x=-2x=−2x, equals, minus, 2, y=5y=5y, equals, 5.

5 0
2 years ago
In the following system of equations, what would you do to eliminate x? 2x + 4y = 10 x - 3y = 12
Anvisha [2.4K]
2x +4y =10x-3y =12

2x +4y =12 -----eq. 1

10x-3y =12 -------eq.2


2x =12 -4y [using eq. 1]
x = (12-4y)/ 2
= 6 -2y

Now, substitute the value of x in eq. 2
10 (6-2y)-3y =10
60 -20y -3y =10
-23 y = 10 -60
y = -50 / -23
y = 50/23


Now, substitute this value of y in any equations given above

10 x-3 (50/23) =12
10x - (150/23)= 12
x= 426/230
8 0
3 years ago
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