4 years ago

If sin (8x-18)=cos (5x+4),what is the value of x?

Mathematics

1 answer:

Ivenika [448]4 years ago

4 0

Hope this helps u..!!!

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Answer:

Step-by-step explanation:

The initial expression is:

$(5x^{3}y^{2}+x^{2}-6x^{2}y^{3})-(3x^{2}y^{3}-4y^{3}+7x^{2})$

Using BEMDAS (Brackets - Exponents - Multiplication - Division - Addition -Subtraction), we first start with brackets:

$5x^{3}y^{2}+x^{2}-6x^{2}y^{3}-3x^{2}y^{3}+4y^{3}-7x^{2}$

Remember that if there is a negative sign, it will change the signs of the terms within the brackets.

Then, collecting like terms:

$5x^{3}y^{2}-9x^{2}y^{3}+4y^{3}-6x^{2}$

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