If m ACD = 30 => m DCB = 60.
In triangle ACD:
![sin 30^{o}=sin \frac{AD}{AC} =\ \textgreater \ \frac{1}{2} = \frac{8}{AC} =\ \textgreater \ AC=16 ](https://tex.z-dn.net/?f=sin%2030%5E%7Bo%7D%3Dsin%20%20%5Cfrac%7BAD%7D%7BAC%7D%20%3D%5C%20%5Ctextgreater%20%5C%20%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%3D%20%20%5Cfrac%7B8%7D%7BAC%7D%20%3D%5C%20%5Ctextgreater%20%5C%20%20AC%3D16%0A)
![CD= 8 \sqrt{3}](https://tex.z-dn.net/?f=CD%3D%208%20%5Csqrt%7B3%7D%20)
![BC= 16\sqrt{3}](https://tex.z-dn.net/?f=BC%3D%2016%5Csqrt%7B3%7D%20)
AC^{2}+CB^{2}=AB^{2} => AB=
![\sqrt{1024}](https://tex.z-dn.net/?f=%20%5Csqrt%7B1024%7D%20)
=32.
=> P=16+32+
![16 \sqrt{3}](https://tex.z-dn.net/?f=16%20%5Csqrt%7B3%7D%20)
=48 +
![16 \sqrt{3}](https://tex.z-dn.net/?f=16%20%5Csqrt%7B3%7D%20)
.
Step-by-step explanation:
The sum of all inner angles in the shape should be 540°
(180° for triangles, 360° for squares and other simple 4-corner-shapes, the pattern is the number of corners minus 2 multiplied by 180°)
we can calculate
540-106-94-135=205
so we got 205 degrees for the two unclear corners and one of them has to be 5° greater.
x is 100°
x is 100°x+5 is 105°
(note that in the subtraction part we could have subtracted 5 more and would be left with 2x=200)
Answer:
3x^3 -8y^2
Step-by-step explanation:
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Answer:
17
Step-by-step explanation:
So the 3 to the power 2 is 9, so 9x2 is 18 so then minus the 1 and it’s 17.