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Finger [1]
3 years ago
10

In which quadrant of the coordinate graph does point F lie? Quadrant I Quadrant II Quadrant III Quadrant IV

Mathematics
2 answers:
shtirl [24]3 years ago
4 0
If it helps quadrant I is in the top right corner, quadrant II is in the top left corner, quadrant 3 in in the bottom left corner, and quadrant IV is in the bottom right corner
mrs_skeptik [129]3 years ago
3 0
Please provide the graph that shows point F.
But, Quadrant 1 is the top right corner, Quadrant 2 is the top left, and it continues like that in a counterclockwise way. 
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What additional information is need
Gelneren [198K]
Umm can you be more specific on your question so I can help you need to explain what you need help on
7 0
3 years ago
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
Expand 4x(7x-11)<br>expand 3x(7-5x)<br>Can someone help me with tge questions above?
melamori03 [73]
<span>(    7 x    -    11    )

<span>(   7   -   5x   )</span></span>
4 0
4 years ago
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An equipment rental company charges a flat rate of $25, plus $13 per day for insurance. Kyle has $121. Write an inequality to re
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121 \geqslant38d
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38. 38


3 \geqslant d
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Identify the variables, the constant, the coefficients, and the exponents in the algebraic expression: 5x + 3y^{2} + 4. (The 2 i
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The variables are: x, y
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