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3 years ago

What is the simplest radical form of the expression? (x^2y^8)^2/3

Mathematics

1 answer:

ryzh [129]3 years ago

6 0

Answer:x^(4/3)y^(16/3)

Step-by-step explanation:

X^(2×2/3)y^(8×2/3)=x^(4/3)y^(16/3)

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According to the Department of Transportation, 27% of domestic flights were delayed in the last year at JFK airport. Five flight

Mars2501 [29]

Answer:

The probability that all the five flights are delayed is 0.2073.

Step-by-step explanation:

Let X = number of domestic flights delayed at JFK airport.

The probability of a domestic flight being delayed at the JFK airport is, P (X) = p = 0.27.

A random sample of n = 5 flights are selected at JFK airport.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={5\choose x}0.27^{x}(1-0.27)^{5-x};\ x=0,1,2...$

Compute the probability that all the five flights are delayed as follows:

$P(X=5)={5\choose 5}0.27^{5}(1-0.27)^{5-5}=1\times 1\times 0.207307=0.2073$

Thus, the probability that all the five flights are delayed is 0.2073.

4 0

3 years ago

What is the averge of 70 and 93?

pychu [463]

Add 70+93, then divide by the number of numbers, which is 2.
70+90=163
163/2=81.5
Hope this helps!

3 0

3 years ago

Read 2 more answers

6th grade math :) only 3 questions

Studentka2010 [4]

Answer:

1.30%

2. 30 questions

3. 60%

Step-by-step explanation:

4 0

3 years ago

How many are 15 x 15 ?

marissa [1.9K]

Answer:

225

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Calls to a customer service center last on average 2.8 minutes with a standard deviation of 1.4 minutes. An operator in the call

Natali5045456 [20]

Answer:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n-values of normal variable:

Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is $M = n\mu$ and the standard deviation is $s = \sigma\sqrt{n}$